Dynamic 365中读取CSV文件

Posted 2020-12-03 sunny-technology

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Dynamic 365开发中对于读取CSV文件与2012略有不同。Dynamic 365中，对于文件的处理是先上传，后下载的过程。需要通过FileUpload control 和Upload strategy class ，FileUploadTemporaryStorageStrategy类来实现对于文件的读取和下载。

以下是一个简单的例子可供参考：

Dilaog窗体，读取文件上传到本地服务器中，以URL方式可以查看

 Public Object dialog()
    {
        DialogGroup      dialogGroup;
        FormBuildControl formBuildControl;
        FileUploadBuild  dialogFileUpload;
        #file
        ;
       
        dialog = super();
        dialogGroup = dialog.addGroup("File path");
        formBuildControl = dialog.formBuildDesign().control(dialogGroup.name());
        dialogFileUpload = formBuildControl.addControlEx(classstr(FileUpload), "dialogFileUpload");
        dialogFileUpload.style(FileUploadStyle::MinimalWithFilename);
        dialogFileUpload.baseFileUploadStrategyClassName(classstr(FileUploadTemporaryStorageStrategy));
        dialogFileUpload.fileTypesAccepted(".csv");
        dialogFileUpload.fileNameLabel("Select a file to upload");
       
        return dialog;
    }

得到控件名：

　　protected FormControl getFormControl(DialogRunbase _dialog, str _controlName)
    　{
        　　return _dialog.formRun().control(_dialog.formRun().controlId( _controlName));
   　 }

获取文件：

public boolean getFromDialog(
    {
        boolean ret;
        ;
        ret = super();
        FileUpload     fileupload;
        fileupload 　=   this.getFormControl(dialog, "dialogFileUpload");

        fileName      = fileupload.fileName();
        if (fileName == ‘‘)
        {
            checkFailed("File name empty");
        }

return ret;
}

读取数据：

private void readData()
{

　　int                               startpos；
        int                              fieldCSVPos;
        container                   conData ;
        SysDictTable             sysDictTable;
        container                   currentLine;
        int                              totalOfLines;

CommaTextStreamIo localStream;

        FileUpload fileUploadControl = this.getFormControl(dialog, “dialogFileUpload”);

        FileUploadTemporaryStorageResult fileUploadResult = fileUploadControl.getFileUploadResult();

        if (fileUploadResult != null && fileUploadResult.getUploadStatus())
        {
            fileName = fileUploadResult.getDownloadUrl();
        }

        localStream = CommaTextStreamIo::constructForRead(File::UseFileFromURL(fileName));


        if (localStream.status() != IO_Status::Ok)
        {
            throw error(strfmt(‘Is not possible to open the file. Error %1‘,enum2str(localStream.status())));
        }