python中将指定的字符串转换为大写字母并每隔2个字符用空格分割后得到一个新字符串的方法

Posted 2020-12-02 luke0011

在例子中对指定的字符串：

faa5fbb5fcc5fdd5010200000028000001900000000a002d00000000017d7840000003e800005fa55fb55fc55fd5

使用了三种方法将其转换为大写字母并每隔2个字符用空格分割处理后得到一个新字符串，为：　

FA A5 FB B5 FC C5 FD D5 01 02 00 00 00 28 00 00 01 90 00 00 00 0A 00 2D 00 00 00 00 01 7D 78 40 00 00 03 E8 00 00 5F A5 5F B5 5F C5 5F D5

为验证三种方法的执行效率，对原字符串扩充为其100倍长度，然后执行10000次处理，从其耗时结果上看，第一种方法最慢，第二、三种方法较好。

代码：

 1 # -*- coding: utf-8 -*-#
 2 
 3 #-------------------------------------------------------------------------------
 4 # Name:         MySplit
 5 # Description:  将指定的字符串转换为大写字母并每隔2个字符用空格分割后得到一个新字符串
 6 # Author:       Administrator
 7 # Date:         2018/7/6
 8 #-------------------------------------------------------------------------------
 9 
10 import re
11 import time
12 
13 #待分割字符串
14 myStr = ‘faa5fbb5fcc5fdd5010200000028000001900000000a002d00000000017d7840000003e800005fa55fb55fc55fd5‘
15 #分割后： FA A5 FB B5 FC C5 FD D5 01 02 00 00 00 28 00 00 01 90 00 00 00 0A 00 2D 00 00 00 00 01 7D 78 40 00 00 03 E8 00 00 5F A5 5F B5 5F C5 5F D5
16 
17 def mySplit1(str):
18     t=‘‘
19     for i in range(len(str)/2):
20         t += str[2*i:2*(i+1)] + ‘ ‘
21     t = t.upper()
22     return t
23 
24 def mySplit2(str):
25     t = str.upper()
26     p = re.compile(‘.{1,2}‘)  # 匹配任意字符1-2次
27     return ‘ ‘.join(p.findall(t))
28 
29 def mySplit3(str):
30     t = str.upper()
31     return ‘ ‘.join([t[2*i:2*(i+1)] for i in range(len(t)/2)])
32 
33 print(‘原始字符串：
‘ + myStr + ‘
‘)
34 print(‘转换后字符串：‘)
35 print(‘mySplit1: ‘ + mySplit1(myStr))
36 print(‘mySplit2: ‘ + mySplit2(myStr))
37 print(‘mySplit3: ‘ + mySplit3(myStr))
38 
39 print(u‘
耗时测试:‘)
40 myStr = myStr * 100
41 for f in [mySplit1, mySplit2, mySplit3]:
42     t = time.time()
43     for i in range(10000):
44         f(myStr)
45     print(f.func_name + ‘: ‘ + str(time.time()-t) + ‘ s‘)

运行结果如下：