python三级菜单的实现

Posted 2020-09-20

#!/usr/bin/env python
# -*- coding: utf-8 -*-
# @Time    : 2017-05-20 2:43
# @Author  : wlgo2108
# @Site    : 
# @File    : Menu01.py
# @Software: PyCharm
# @Email   : [email protected]

import re
import sys

menu = {
    "M:主菜单":{
        "L:登录管理":{
            "LU:修改密码":{},
            "LR:密码复位":{},
            "LL:重新登录":{},
            "LH:挂起系统":{}
        },
        "C:客户管理":{
            "CM:客户信息管理":{
                "CMA:添加客户":{},
                "CMU:更新客户":{}
            },
            "CR:客户关系维护":{}
        },
        "S:系统管理":{
            "SU:用户管理":{
                "SUA:添加用户":{},
                "SUU:更新用户":{}
            },
            "SL:权限管理":{
                "SLL:授权":{},
                "SLC:取消权限":{}
            },
            "SH:假日参数":{}
        }
    }
}

his_menu = ["M","M"]
cur_menu = menu
flag = False


def check_menu(menu_dict={},key=""):
    if isinstance(menu_dict,dict):
        for k,v in menu_dict.items():
            if key == k.split(":")[0]:
                c_menu = dict(v)
                set_his_menu(key)
                for k in c_menu:
                    print(k)
                return True
            elif isinstance(v,dict):
                check_menu(v,key)
    return False


def set_his_menu(key) :
    his_menu[0] = his_menu[1]
    his_menu.remove(his_menu[1])
    his_menu.append(key)
    print(his_menu)

for k in cur_menu:
    print(k)

while not flag:
    key = str(input("输入菜单快捷键:")).strip().upper()
    if re.match("Q|E",key):
        print("退出系统")
        sys.exit(0)
    elif re.match("B",key):
        key = his_menu[0]
        check_menu(menu_dict=cur_menu,key=key)
    else:
        check_menu(menu_dict=cur_menu,key=key)