python练习_module02-1-员工信息表

Posted 2020-09-17

python 操作 员工信息表

• 要求：

• 可进行模糊查询，语法至少支持下面3种: 

  select name,age from staff_table where age > 22
  select * from staff_table where dept = "IT"
  select * from staff_table where enroll_date like "2013"

  查到的信息，打印后，最后面还要显示查到的条数

• 可创建新员工纪录，以phone做唯一键，staff_id需自增 

• 可删除指定员工信息纪录，输入员工id，即可删除 

• 可修改员工信息，语法如下:
  　　UPDATE staff_table SET dept="Market" WHERE where dept = "IT"
  注意：以上需求，要充分使用函数，请尽你的最大限度来减少重复代码

• 达成要求：
• 查询命令的各单词之间可以有任意数量的空格
• 查询时不设定条件（where语句）也可以执行
• 错误信息高亮显示
• 代码：

 

#!  /usr/bin/env python3
#   Author:Jailly

import pickle,re

# 查找
def search(search_condition):
    res = []  # 储存查找结果

    # where条件存在
    if search_condition:
        # 三种条件格式
        m1 = re.search(r‘age\s+(>|<)\s+(0|([1-9]\d*))‘, search_condition)
        m2 = re.search(r‘‘‘
            (?P<category>(staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date))
            \s+=\s+
            (?P<value>.*)
            ‘‘‘, search_condition, re.X)
        m3 = re.search(r‘‘‘
            (?P<category>(staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date))
            \s+like\s+
            (?P<value>[1-9]\d*)
            ‘‘‘, search_condition, re.X)

        # age <|> \d 的情况
        if m1:
            # 筛选条目
            for i in staff_table:
                info_dict = dict(zip([‘staff_id‘, ‘name‘, ‘age‘, ‘phone‘, ‘dept‘, ‘enroll_date‘], i))
                if eval(m1.group().replace(‘age‘, str(i[2]))):
                    res.append(info_dict)

        # category = \w+ 的情况
        elif m2:
            # 筛选条目
            for i in staff_table:
                # 对应信息表中每个条目的字典
                info_dict = dict(zip([‘staff_id‘, ‘name‘, ‘age‘, ‘phone‘, ‘dept‘, ‘enroll_date‘], i))
                if str(info_dict[m2.group(‘category‘)]) == m2.group(‘value‘).strip():
                    res.append(info_dict)

        # category like \w+ 的情况
        elif m3:
            for i in staff_table:
                info_dict = dict(
                    zip([‘staff_id‘, ‘name‘, ‘age‘, ‘phone‘, ‘dept‘, ‘enroll_date‘], i))  # 对应每个条目的字典
                if info_dict[m3.group(‘category‘)].count(m3.group(‘value‘)) or                         str(info_dict[m3.group(‘category‘)]).count(str(m3.group(‘value‘))):
                    res.append(info_dict)

        # 条件格式不正确的情况
        else:
            print(‘\033[1;31mwhere语句格式错误！\033[0m‘)

    # 无where条件
    else:
         for i in staff_table:
            info_dict = dict(zip([‘staff_id‘, ‘name‘, ‘age‘, ‘phone‘, ‘dept‘, ‘enroll_date‘], i))
            res.append(info_dict)
    return res

# 显示查找结果
def show(res, search_categories):
    if res:
        for i in res:
            # 查询所有条目 *
            if search_categories.strip() == ‘*‘:
                print(‘,‘.join([str(i[‘staff_id‘]), i[‘name‘], str(i[‘age‘]), i[‘phone‘], i[‘dept‘], i[‘enroll_date‘]]))
            # 查询指定条目 name,age,...
            else:
                category_list = search_categories.split(‘,‘)
                for j in category_list:
                    print(i[j.strip()], end=‘,‘)
                print()

        print(‘\n共查找到%d条记录\n‘ % len(res))

# 保存文件
def save():
    with open(‘staff_table.pkl‘, ‘wb‘) as f:
        pickle.dump(staff_table, f)


if __name__ == ‘__main__‘:
    while 1:
        with open(‘staff_table.pkl‘, ‘rb‘) as f:
            staff_table = pickle.load(f)

        cmd = input(‘command -> ‘)

        # 查询指令
        search_cmd = re.search(r‘‘‘
            ^\s*select\s+
            (?P<categories>\*|
            (
            ((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date))
            (\s*,\s*((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date)))?
            (\s*,\s*((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date)))?
            (\s*,\s*((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date)))?
            (\s*,\s*((staff_id)|(name)|(age)|(phone)|(dept)|(enroll_date)))?)
            )
            \s+from\s+staff_table
            (\s+where\s+
            (?P<condition>.*))?$‘‘‘,cmd,re.X)

        # 添加指令
        insert_cmd = re.search(r‘‘‘
            ^\s*[\w ]+,  # 姓名
            [1-9]\d*,  # 年龄
            \d{11},  # 手机号码
            [\w ]+,  # 部门
            ((20)|(19))\d{2}-((10)|(11)|(12)|(0[1-9]))-(([0-2][1-9])|(3[01]))$  # 入职日期
            ‘‘‘,cmd,re.X)

        # 删除指令
        delete_cmd = re.search(r‘^\d+$‘,cmd)

        # 更改指令
        update_cmd = re.search(r‘‘‘
            ^update\s+staff_table\s+set\s+
            (?P<category_update>(name)|(age)|(phone)|(dept)|(enroll_date))\s+
            =\s+
            (‘|")(?P<new_value>.*)(‘|")
            (\s+where\s+
            (?P<condition>.*))?$
            ‘‘‘,cmd,re.X)

        # 查询
        if search_cmd:
            search_categories = search_cmd.group(‘categories‘)
            search_condition = search_cmd.group(‘condition‘)

            res = search(search_condition)
            show(res,search_categories)

        # 添加
        elif insert_cmd:
            insert_list = insert_cmd.group().split(‘,‘)

            repeat_flag = 0
            for i in staff_table:
                if insert_list[2] == i[3]:
                    print(‘\033[1;31m手机号码已存在!\033[0m‘)
                    repeat_flag = 1
                    break
            else:
                insert_list.insert(0,( staff_table[-1][0] + 1 ) )
                staff_table.append(insert_list)

                save()
                print(‘添加成功！‘)

        # 删除
        elif delete_cmd:
            for i in staff_table:
                if delete_cmd.group() == str(i[0]):
                    staff_table.remove(i)
                    save()
                    print(‘删除成功！‘)
                    break
            else:
                print(‘\033[1;31m该staff_id不存在\033[0m‘)

        # 修改
        elif update_cmd:
            search_condition = update_cmd.group(‘condition‘)

            res = search(search_condition)
            for i in range(len(staff_table)):
                for j in res:
                    if staff_table[i][0] == j[‘staff_id‘]:
                        category_update = update_cmd.group(‘category_update‘)
                        new_value = update_cmd.group(‘new_value‘).strip()
                        j[category_update] = int(new_value) if category_update == ‘age‘ else new_value

                        # 保证顺序，不能用list(j.values())
                        staff_table[i] = list([j[‘staff_id‘],j[‘name‘],j[‘age‘],j[‘phone‘],j[‘dept‘],j[‘enroll_date‘]])

            save()
            print(‘修改成功！‘)

        # 退出
        elif cmd == ‘q‘:
            break

        # 输入格式不正确的情况
        else:
            print(‘\033[1;31m输入格式错误\033[0m‘)