习题10-1 判断满足条件的三位数 (15 分)

Posted 2022-02-19 JamesGordan

#include <stdio.h>
#include <math.h>

int search(int n);

int main()

    int number;

    scanf("%d", &number);
    printf("count=%d\\n", search(number));
    system("pause");
    return 0;



/* 你的代码将被嵌在这里 */
int search(int n) 
    int count = 0;
    int a1, a2, a3;
    for (int i = 11; i*i < n; i++) 
        a1 = i * i % 10;
        a2 = i * i / 10 % 10;
        a3 = i * i / 100;
        if (a1 == a2 || a1 == a3 || a2 == a3)
            count++;
    
    return count;