SQL-Update语句

Posted 2022-01-26 奇遇yms

 

 根据 levelCodeName 更新  levelCode

建表语句

CREATE TABLE `sy_cd_ms_tag_level` (
  `id` int(10) NOT NULL AUTO_INCREMENT,
  `bigId` int(10) NOT NULL COMMENT \'大类编码\',
  `bigName` varchar(100) COLLATE utf8_bin DEFAULT NULL COMMENT \'大类名称\',
  `fieldCode` int(2) DEFAULT NULL COMMENT \'来源字段类型\',
  `fieldCodeName` varchar(100) COLLATE utf8_bin DEFAULT NULL COMMENT \'范围类型名称\',
  `levelScore` int(10) NOT NULL,
  `levelCodeName` varchar(100) COLLATE utf8_bin DEFAULT NULL COMMENT \'相关度等名称\',
  `levelCode` int(2) DEFAULT NULL COMMENT \'相关度等级代码\',
  PRIMARY KEY (`id`),
  KEY `bigId_idx` (`bigId`),
  KEY `fieldCode_idx` (`fieldCode`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_bin;

更新语句

UPDATE sy_cd_ms_tag_level t1,(
SELECT id,levelCodeName,
CASE WHEN levelCodeName = \'五星级\'  THEN \'5\' 
WHEN levelCodeName = \'四星级\'  THEN \'4\' 
WHEN levelCodeName = \'三星级\'  THEN \'3\' 
WHEN levelCodeName = \'二星级\'  THEN \'2\' 
WHEN levelCodeName = \'一星级\'  THEN \'1\' 
WHEN levelCodeName = \'零星级\'  THEN \'0\' 
END as levelCode
FROM sy_cd_ms_tag_level
)t2
set t1.levelCode=t2.levelCode
where t1.id=t2.id