c语言－－键盘输入数字，输出汉字读法

Posted 2023-03-14

例如：我输入4561。要求输出四千五百六十一
输入254。要求输出二百五十四
输入40001,输出四万零一
输入数字w,0<w<=99999999

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char *change(char ch)

static char shu[3];
memset(shu, 0, 3);
switch(ch)

case '1':strcpy(shu,"一");break;
case '2':strcpy(shu,"二");break;
case '3':strcpy(shu,"三");break;
case '4':strcpy(shu,"四");break;
case '5':strcpy(shu,"五");break;
case '6':strcpy(shu,"六");break;
case '7':strcpy(shu,"七");break;
case '8':strcpy(shu,"八");break;
case '9':strcpy(shu,"九");break;
case '0':strcpy(shu,"零");break;
default:printf("输入有误!");exit(0);

return shu;


char *func(char *s, int len)

int i, j;
char *dest;
char *shu;
char *wei[4]="千","百","十","";

dest = (char *)malloc(64);
memset(dest, 0, 64);
switch(len)

case 1:j=3;break;
case 2:j=2;break;
case 3:j=1;break;
case 4:j=0;break;

for(i=0;i<len;i++)

shu = change(*(s+i));
if( !(i>0&&*(s+i-1)=='0'&&*(s+i)=='0') )

strcat(dest, shu);
if(*(s+i)!='0')
strcat(dest, wei[j+i]);


if( (strlen(dest)>2) && (strcmp(shu,"零")==0) )dest[strlen(dest)-2]='\0';
return dest;


int main()

int len;
char num[10];
char *hanzi, *tmp;

hanzi = (char *)malloc(64);
tmp = (char *)malloc(32);

printf("输入数字，1~99999999:");
gets(num);
len = strlen(num);
memset(hanzi, 0, 64);
memset(tmp, 0, 32);
if(len>4)

hanzi = func(num, len-4);
strcat(hanzi, "万");
tmp = func(num+len-4, 4);
if(strcmp(tmp, "零")!=0)
strcat(hanzi, tmp);

else hanzi = func(num, len);
printf("汉字读法:");
puts(hanzi);

free(hanzi);
free(tmp);
return 0;
参考技术A 用数组把没位上的数字都保存下来，在写个循环用switch语句进行转换就可以了，这个没有什么难度的