Python将numpy数组的列表转换为2d数组

Posted 2021-04-02

这是我的numpy数组列表：

[阵列（[0.33007796,0.10620873，-0.03484848，-0.168602,0.4564025,0.11370123，-0.37691383，-0.10863657，-0.16251889,0.02544368，-0.03327211,0.23185516，-0.32642304，-0.15969283,0.45812119,0.24997875,0.13897375,0.01468147，-0.15773412 ，-0.53704494，-0.06121204,0.19579619,0.30438485,0.05908984,0.29759387，-1.61107886，-0.55878418,0.06553798,0.37648846，-0.35247216,3.33212613,0.22318645，-0.21187862，-0.39089783,0.05294092，-0.0413471,0.02179677,0.25394103,0.01980207， - 0.22377998，-0.08718371,0.02940335,0.02797039,0.34935868，-0.05733391,0.07754561，-0.0972822,0.05259355，-0.0562219,0.15573672]）

阵列（[0.20259871,0.12458311，-0.20787658，-0.16353745,0.40842594,0.25567385，-0.2703993，-0.15097566，-0.13328776，-0.0331789,0.02034447,0.07318579，-0.22284479，-0.19045474,0.23279801,0.11366921,0.11914298，-0.09647366，-0.20951753 ，-0.22698855，-0.045307,0.11098107,0.0524313，-0.0424848,0.11007177，-1.51343118，-0.36741486，-0.05812052,0.13435007，-0.09786326,2.84255649,0.00325309，-0.27484909，-0.47422259，-0.03957974，-0.13663797，-0.03203189,0.0155929 ，-0.06982855，-0.08388657，-0.16572997,0.04573543，-0.00667479,0.21973781，-0.14895521,0.1210014，-0.21911705，-0.05924631，-0.07265716，-0.10153842]）]

但是我想要这个：

[[ 0.33007796, 0.10620873, -0.03484848, -0.168602 , 0.4564025 , 0.11370123, -0.37691383, -0.10863657, -0.16251889, 0.02544368, -0.03327211, 0.23185516, -0.32642304, -0.15969283, 0.45812119, 0.24997875, 0.13897375, 0.01468147, -0.15773412, -0.53704494, -0.06121204, 0.19579619, 0.30438485, 0.05908984, 0.29759387, -1.61107886, -0.55878418, 0.06553798, 0.37648846, -0.35247216, 3.33212613, 0.22318645, -0.21187862, -0.39089783, 0.05294092, -0.0413471 , 0.02179677, 0.25394103, 0.01980207, -0.22377998, -0.08718371, 0.02940335, 0.02797039, 0.34935868, -0.05733391, 0.07754561, -0.0972822 , 0.05259355, -0.0562219 , 0.15573672]

[ 0.20259871, 0.12458311, -0.20787658, -0.16353745, 0.40842594, 0.25567385, -0.2703993 , -0.15097566, -0.13328776, -0.0331789 , 0.02034447, 0.07318579, -0.22284479, -0.19045474, 0.23279801, 0.11366921, 0.11914298, -0.09647366, -0.20951753, -0.22698855, -0.045307 , 0.11098107, 0.0524313 , -0.0424848 , 0.11007177, -1.51343118, -0.36741486, -0.05812052, 0.13435007, -0.09786326, 2.84255649, 0.00325309, -0.27484909, -0.47422259, -0.03957974, -0.13663797, -0.03203189, 0.0155929 , -0.06982855, -0.08388657, -0.16572997, 0.04573543, -0.00667479, 0.21973781, -0.14895521, 0.1210014 , -0.21911705, -0.05924631, -0.07265716, -0.10153842]]

我尝试了什么：

X_transform = [list(x) for x in X_transform]

但不幸的是抛出：TypeError: 'numpy.float64' object is not iterable

我也试过它给的X_transform.tolist()（不是我想要的）：

[阵列（[0.33007796,0.10620873，-0.03484848，-0.168602,0.4564025,0.11370123，-0.37691383，-0.10863657，-0.16251889,0.02544368，-0.03327211,0.23185516，-0.32642304，-0.15969283,0.45812119,0.24997875,0.13897375,0.01468147，-0.15773412 ，-0.53704494，-0.06121204,0.19579619,0.30438485,0.05908984,0.29759387，-1.61107886，-0.55878418,0.06553798,0.37648846，-0.35247216,3.33212613,0.22318645，-0.21187862，-0.39089783,0.05294092，-0.0413471,0.02179677,0.25394103,0.01980207， - 0.22377998，-0.08718371,0.02940335,0.02797039,0.34935868，-0.05733391,0.07754561，-0.0972822,0.05259355，-0.0562219,0.15573672]），

阵列（[0.20259871,0.12458311，-0.20787658，-0.16353745,0.40842594,0.25567385，-0.2703993，-0.15097566，-0.13328776，-0.0331789,0.02034447,0.07318579，-0.22284479，-0.19045474,0.23279801,0.11366921,0.11914298，-0.09647366，-0.20951753 ，-0.22698855，-0.045307,0.11098107,0.0524313，-0.0424848,0.11007177，-1.51343118，-0.36741486，-0.05812052,0.13435007，-0.09786326,2.84255649,0.00325309，-0.27484909，-0.47422259，-0.03957974，-0.13663797，-0.03203189,0.0155929 ，-0.06982855，-0.08388657，-0.16572997,0.04573543，-0.00667479,0.21973781，-0.14895521,0.1210014，-0.21911705，-0.05924631，-0.07265716，-0.10153842]）]

我也尝试过：

a = []
for i in range(1000):
    a.append([X_transform[i][0]])

但它抛出了IndexError: invalid index to scalar variable.

最后我试过：

X_transform = np.stack(X_transform)

它抛出：ValueError: all input arrays must have the same shape

答案

不确定这是否是你要求的，但让我们试试[iPython]：

In [1]: import numpy as np
   ...: a = np.stack([np.array([1,2,3]), np.array([11,12,13])])
   ...: print a.shape
   ...: print a
   ...: 
(2, 3)
[[ 1  2  3]
 [11 12 13]]

另一答案

你可以尝试使用np.asarray()

这是一个例子：

>>> import numpy as np
>>> a = np.arange(6) + 10
>>> a
array([10, 11, 12, 13, 14, 15])
>>> b = np.arange(6) + 20
>>> b
array([20, 21, 22, 23, 24, 25])
>>> c = [a, b]
>>> c
[array([10, 11, 12, 13, 14, 15]), array([20, 21, 22, 23, 24, 25])]
>>> e = np.asarray(c)
>>> e
array([[10, 11, 12, 13, 14, 15],
       [20, 21, 22, 23, 24, 25]])

另一答案

如果我得到你所说的你有一个清单

l  = [np.array([ 0.33007796, 0.10620873, -0.03484848, -0.168602 , 0.4564025 , 0.11370123, -0.37691383, -0.10863657, -0.16251889, 0.02544368, -0.03327211, 0.23185516, -0.32642304, -0.15969283, 0.45812119, 0.24997875, 0.13897375, 0.01468147, -0.15773412, -0.53704494, -0.06121204, 0.19579619, 0.30438485, 0.05908984, 0.29759387, -1.61107886, -0.55878418, 0.06553798, 0.37648846, -0.35247216, 3.33212613, 0.22318645, -0.21187862, -0.39089783, 0.05294092, -0.0413471 , 0.02179677, 0.25394103, 0.01980207, -0.22377998, -0.08718371, 0.02940335, 0.02797039, 0.34935868, -0.05733391, 0.07754561, -0.0972822 , 0.05259355, -0.0562219 , 0.15573672]),
      np.array([ 0.20259871, 0.12458311, -0.20787658, -0.16353745, 0.40842594, 0.25567385, -0.2703993 , -0.15097566, -0.13328776, -0.0331789 , 0.02034447, 0.07318579, -0.22284479, -0.19045474, 0.23279801, 0.11366921, 0.11914298, -0.09647366, -0.20951753, -0.22698855, -0.045307 , 0.11098107, 0.0524313 , -0.0424848 , 0.11007177, -1.51343118, -0.36741486, -0.05812052, 0.13435007, -0.09786326, 2.84255649, 0.00325309, -0.27484909, -0.47422259, -0.03957974, -0.13663797, -0.03203189, 0.0155929 , -0.06982855, -0.08388657, -0.16572997, 0.04573543, -0.00667479, 0.21973781, -0.14895521, 0.1210014 , -0.21911705, -0.05924631, -0.07265716, -0.10153842])]

然后这应该将其转换为您想要的格式：

new_l = [list(i) for i in l]

我认为你所做的错误是X_transform不是完整的列表，而只是列表中的一个numpy数组，所以它的元素是浮点数，而不是numpy数组，因此引发了错误。

另一答案

让我们定义u如下：

import numpy as np
u = [np.array(range(24)),np.array(range(24))]
u
>>>[array([ 0,  1,  2,  3,  4,  5,  6,  7,  8,  9, 10]), array([ 0,  1,  2,  3,  4,  5,  6,  7,  8,  9])]

然后我会使用list comprehension将你转换为列表，如下所示。

v = [val.tolist() for val in u]

print(v)

>>> [[0, 1, 2, 3, 4, 5, 6, 7, 8, 9], [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]]