python3之利用字典和列表实现城市多级菜单

Posted 2021-03-21 exception999

利用字典和列表实现城市多级菜单

 1 #coding:utf-8
 2 #利用字典和列表实现城市多级菜单
 3 addrIndex = {"1":"北京","2":"上海","3":"南京","4":"福建"}
 4 addrDict = {"北京":["东城区","西城区","大兴区"],"上海":["黄浦区","长宁区","宝山区"],"南京":["玄武区","秦淮区","六合区"],"福建":["龙岩","泉州"]}
 5 while True:
 6     i = 1
 7     #循环打印城市名称
 8     for cs in addrDict.keys():
 9         print("%d.%s" %(i,cs))
10         i += 1
11     choIndex = input("请输入你城市编号：")
12 
13     #为每个城市指定编号值，便于判断输入错误和扩展
14     if choIndex not in addrIndex.keys():
15         print("输入有误！")
16         continue
17     # print(addrDict[addrIndex[choIndex]])
18 
19     while True:
20         i = 1
21         #根据输入的城市编号，获取城市名称，城市名称直接为addrDict字典的key
22         for pq in addrDict[addrIndex[choIndex]]:
23             print("%d.%s" %(i,pq))
24             i += 1
25         pqCho = input("请输入片区编号,输入q返回上级：")
26 
27         #输入q跳出
28         if pqCho == "q":
29             break
30         #输入正确的值打印，pqCho.isdigit()用于判断输入非q字符串错误
31         elif pqCho.isdigit() and (int)(pqCho)-1>=0 and (int)(pqCho)-1<=len(addrDict[addrIndex[choIndex]])-1:
32             print("你选择的是:%s" %(addrDict[addrIndex[choIndex]][(int)(pqCho)-1]))
33         else:
34             print("输入有误！")
35             continue