with open()函数中,如何在文件名设置中引用变量（python）

Posted 2021-03-20 看星星的派大星

name = "wangyang"
age = "25"

with open("C:/Users/mike1/Desktop/name_age.txt", "w", encoding = "utf-8") as f1:
    f1.write("hellow world")


    

这么写是不行的，文件名是name_age.txt,而不是wangyang_25.txt.

如下图：

 

 

 

正确的方式应该是用format()函数

name = "wangyang"
age = "25"

with open("C:/Users/mike1/Desktop/{0}_{1}.txt".format(name, age), "w", encoding = "utf-8") as f1:
    f1.write("hellow world")

如下图所示:

 

 

 

关于format() 的一些基本的用法：

 

 

number = 3.1415926
print("{0:f},{0:%},{0:e}".format(number))

 

 当然还可以动%来格式化就像C语言一样。

name = "wangyang"
age = 25
price = 99999.9999999
print("my name is %s"%(name))
print("my age is %d"%(age))
print("my price is %f"%(price))