Python 操作SQLite数据库
Posted LyShark
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Python 操作SQLite数据库相关的知识,希望对你有一定的参考价值。
SQLite,是一款轻型的数据库,是遵守ACID的关系型数据库管理系统,它包含在一个相对小的C库中。在很多嵌入式产品中使用了它,它占用资源非常的低,python 中默认继承了操作此款数据库的引擎 sqlite3 说是引擎不如说就是数据库的封装版,开发自用小程序的使用使用它真的大赞
简单操作SQLite数据库:创建 sqlite数据库是一个轻量级的数据库服务器,该模块默认集成在python中,开发小应用很不错.
import sqlite3
# 数据表的创建
conn = sqlite3.connect("data.db")
cursor = conn.cursor()
create = "create table persion(" "id int auto_increment primary key," "name char(20) not null," "age int not null," "msg text default null" ")"
cursor.execute(create) # 执行创建表操作
简单操作SQLite数据库:简单的插入语句的使用
insert = "insert into persion(id,name,age,msg) values(1,'lyshark',1,'hello lyshark');"
cursor.execute(insert)
insert = "insert into persion(id,name,age,msg) values(2,'guest',2,'hello guest');"
cursor.execute(insert)
insert = "insert into persion(id,name,age,msg) values(3,'admin',3,'hello admin');"
cursor.execute(insert)
insert = "insert into persion(id,name,age,msg) values(4,'wang',4,'hello wang');"
cursor.execute(insert)
insert = "insert into persion(id,name,age,msg) values(5,'sqlite',5,'hello sql');"
cursor.execute(insert)
data = [(6, '王舞',8, 'python'), (7, '曲奇',8,'python'), (9, 'C语言',9,'python')]
insert = "insert into persion(id,name,age,msg) values(?,?,?,?);"
cursor.executemany(insert,data)
简单的查询语句的使用
select = "select * from persion;"
cursor.execute(select)
#print(cursor.fetchall()) # 取出所有的数据
select = "select * from persion where name='lyshark';"
cursor.execute(select)
print(cursor.fetchall()) # 取出所有的数据
select = "select * from persion where id >=1 and id <=2;"
list = cursor.execute(select)
for i in list.fetchall():
print("字段1:", i[0])
print("字段2:", i[1])
简单的更新数据与删除
update = "update persion set name='苍老师' where id=1;"
cursor.execute(update)
update = "update persion set name='苍老师' where id>=1 and id<=3;"
cursor.execute(update)
delete = "delete from persion where id=3;"
cursor.execute(delete)
select = "select * from persion;"
cursor.execute(select)
print(cursor.fetchall()) # 取出所有的数据
conn.commit() # 事务提交,每执行一次数据库更改的操作,就执行提交
cursor.close()
conn.close()
SQLite小试牛刀 实现用户名密码验证,当用户输入错误密码后,自动锁定该用户1分钟.
import sqlite3
import re,time
conn = sqlite3.connect("data.db")
cursor = conn.cursor()
"""create = "create table login(" "username text not null," "password text not null," "time int default 0" ")"
cursor.execute(create)
cursor.execute("insert into login(username,password) values('admin','123123');")
cursor.execute("insert into login(username,password) values('guest','123123');")
cursor.execute("insert into login(username,password) values('lyshark','1231');")
conn.commit()"""
while True:
username = input("username:") # 这个地方应该严谨验证,尽量不要让用户拼接SQL语句
password = input("passwor:") # 此处为了方便不做任何验证(注意:永远不要相信用户的输入)
sql = "select * from login where username='{}'".format(username)
ret = cursor.execute(sql).fetchall()
if len(ret) != 0:
now_time = int(time.time())
if ret[0][3] <= now_time:
print("当前用户{}没有被限制,允许登录...".format(username))
if ret[0][0] == username:
if ret[0][1] == password:
print("用户 {} 登录成功...".format(username))
else:
print("用户 {} 密码输入有误..".format(username))
times = int(time.time()) + 60
cursor.execute("update login set time={} where username='{}'".format(times,username))
conn.commit()
else:
print("用户名正确,但是密码错误了...")
else:
print("账户 {} 还在限制登陆阶段,请等待1分钟...".format(username))
else:
print("用户名输入错误")
SQLite检索时间记录 通过编写的TimeIndex函数检索一个指定范围时间戳中的数据.
import os,time,datetime
import sqlite3
"""
conn = sqlite3.connect("data.db")
cursor = conn.cursor()
create = "create table lyshark(" "time int primary key," "cpu int not null" ")"
cursor.execute(create)
# 批量生成一堆数据,用于后期的测试.
for i in range(1,500):
times = int(time.time())
insert = "insert into lyshark(time,cpu) values({},{})".format(times,i)
cursor.execute(insert)
conn.commit()
time.sleep(1)"""
# db = data.db 传入数据库名称
# table = 指定表lyshark名称
# start = 2019-12-12 14:28:00
# ends = 2019-12-12 14:29:20
def TimeIndex(db,table,start,ends):
start_time = int(time.mktime(time.strptime(start,"%Y-%m-%d %H:%M:%S")))
end_time = int(time.mktime(time.strptime(ends,"%Y-%m-%d %H:%M:%S")))
conn = sqlite3.connect(db)
cursor = conn.cursor()
select = "select * from {} where time >= {} and time <= {}".format(table,start_time,end_time)
return cursor.execute(select).fetchall()
if __name__ == "__main__":
temp = TimeIndex("data.db","lyshark","2019-12-12 14:28:00","2019-12-12 14:29:00")
print(temp)
SQLite提取数据并绘图 通过使用matplotlib这个库函数,并提取出指定时间的数据记录,然后直接绘制曲线图.
import os,time,datetime
import sqlite3
import numpy as np
from matplotlib import pyplot as plt
def TimeIndex(db,table,start,ends):
start_time = int(time.mktime(time.strptime(start,"%Y-%m-%d %H:%M:%S")))
end_time = int(time.mktime(time.strptime(ends,"%Y-%m-%d %H:%M:%S")))
conn = sqlite3.connect(db)
cursor = conn.cursor()
select = "select * from {} where time >= {} and time <= {}".format(table,start_time,end_time)
return cursor.execute(select).fetchall()
def Display():
temp = TimeIndex("data.db","lyshark","2019-12-12 14:28:00","2019-12-12 14:29:00")
list = []
for i in range(0,len(temp)):
list.append(temp[i][1])
plt.title("CPU Count")
plt.plot(list, list)
plt.show()
if __name__ == "__main__":
Display()
以上是关于Python 操作SQLite数据库的主要内容,如果未能解决你的问题,请参考以下文章
当我从用户获取数据并将其保存到 SQLite 数据库中时,我应该怎么做才能使列表视图在片段中工作
Android 逆向使用 DB Browser 查看并修改 SQLite 数据库 ( 从 Android 应用数据目录中拷贝数据库文件 | 使用 DB Browser 工具查看数据块文件 )(代码片段
Android 逆向使用 DB Browser 查看并修改 SQLite 数据库 ( 从 Android 应用数据目录中拷贝数据库文件 | 使用 DB Browser 工具查看数据块文件 )(代码片段