Python:elapsedu time（给定总秒数的人类可读时间跨度）

Posted 2021-02-27

This function takes an amount of time in seconds and returns a human readable time span (i.e., 4h 5m 23s). The suffixes (d for day, h for hour) are configurable to whatever you want (like day, hour, week, etc). Read the comments within the code for more detail.

def elapsed_time(seconds, suffixes=['y','w','d','h','m','s'], add_s=False, separator=' '):
	"""
	Takes an amount of seconds and turns it into a human-readable amount of time.
	"""
	# the formatted time string to be returned
	time = []
 
	# the pieces of time to iterate over (days, hours, minutes, etc)
	# - the first piece in each tuple is the suffix (d, h, w)
	# - the second piece is the length in seconds (a day is 60s * 60m * 24h)
	parts = [(suffixes[0], 60 * 60 * 24 * 7 * 52),
		  (suffixes[1], 60 * 60 * 24 * 7),
		  (suffixes[2], 60 * 60 * 24),
		  (suffixes[3], 60 * 60),
		  (suffixes[4], 60),
		  (suffixes[5], 1)]
 
	# for each time piece, grab the value and remaining seconds, and add it to
	# the time string
	for suffix, length in parts:
		value = seconds / length
		if value > 0:
			seconds = seconds % length
			time.append('%s%s' % (str(value),
					       (suffix, (suffix, suffix + 's')[value > 1])[add_s]))
		if seconds < 1:
			break
 
	return separator.join(time)
 
if __name__ == '__main__':
	# 2 years, 1 week, 6 days, 2 hours, 59 minutes, 23 seconds
	# 2y 1w 6d 2h 59m 23s
	seconds = (60 * 60 * 24 * 7 * 52 * 2) + (60 * 60 * 24 * 7 * 1) + (60 * 60 * 24 * 6) + (60 * 60 * 2) + (60 * 59) + (1 * 23)
	print elapsed_time(seconds)
	print elapsed_time(seconds, [' year',' week',' day',' hour',' minute',' second'])
	print elapsed_time(seconds, [' year',' week',' day',' hour',' minute',' second'], add_s=True)
	print elapsed_time(seconds, [' year',' week',' day',' hour',' minute',' second'], add_s=True, separator=', ')