在Python中创建更好的slug

Posted 2021-02-24

I only did some improvements over another snippet.

# -*- coding: utf-8 -*-
import htmlentitydefs, re
 
def slugfy(text, separator="-"):
	ret = ""
	for c in text.lower():
		try:
			ret += htmlentitydefs.codepoint2name[ord(c)]
		except:
			ret += c
 
	ret = re.sub("([a-zA-Z])(uml|acute|grave|circ|tilde|cedil)", r"1", ret)
	ret = ret.strip()
	ret = re.sub(" ", "_", ret)
	ret = re.sub("W", "", ret)
	ret = re.sub("[ _]+", separator, ret)
 
	return ret.strip()