四种类型转换符

Posted 2023-06-19 im18620660608

C++中常见的面试题.

题目: 关于C++中, 四种类型转换的关键字, 的详解, 也可以给出代码, 判断输出 或 判断哪些代码有误.

 

答案及范例如下:

 

四种关键字: const_cast, 常量性转除;dynamic_cast, 向下安全转型;reinterpret_cast, 重新解释转型; static_cast, 静态转型;

1. const_cast, 常量性转除:

主要对变量的常量性(const)进行操作, 移除变量的常量性, 即可以被非常量指向和引用, 详见代码;

2. dynamic_cast, 向下安全转型:

主要应用于继承体系, 可以由 指向派生类的基类部分的指针, 转换指向派生类或指向兄弟类;

static_cast只能转换为指向派生类;

3. reinterpret_cast, 重新解释转型:

主要是对2进制数据进行重新解释(re-interpret),不改变格式, 而static_cast会改变格式进行解释;

如由派生类转换基类, 则重新解释转换, 不改变地址, 静态转换改变地址;

4. static_cast, 静态转型:

主要是数据类型的转换, 还可以用于继承;

 

代码如下:

 

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/*  * cppprimer.cpp  *  *  Created on: 2014.2.10  *      Author: Spike  */   /*eclipse cdt, gcc 4.8.1*/   #include <iostream>   /*常量性移除指针详解*/   struct S     S() : value(0)     int value; ;   void CastConst (void)     const S s;     std::cout << s.value =  << s.value << std::endl;     //S* ps = &s; //error, 指向常量     S* ps = const_cast<s*>(&s);     ps->value = 1;     std::cout << s.value =  << s.value << std::endl;     //S& rs = s; //error, 引用常量     S& rs = const_cast<s&>(s);     rs.value = 2;     std::cout << s.value =  << s.value << std::endl;   /*安全向下转型*/   struct B /*基类B*/     virtual void f() std::cout << Base::f << std::endl;     void thisf() std::cout << Base::thisf << std::endl;     virtual ~B() ;   struct B2 /*基类B2*/     virtual void g() std::cout << Base2::g << std::endl;     void thisg() std::cout << Base2::thisg << std::endl;     virtual ~B2() ;   struct D : public B, public B2 /*派生类D*/     virtual void f() std::cout << Derived::f << std::endl;     virtual void g() std::cout << Derived::g << std::endl;     virtual ~D() ;   void CastDynamic (void)      B* pB_D = new D;      pB_D->f();      //pD->g(); //error, 只包含B部分        D *pD_D = dynamic_cast<d*>(pB_D); //转换为派生类      pD_D->g();      B2* pB2_D = dynamic_cast<b2*>(pB_D); //转换为兄弟类      pB2_D->g();        D *pD_Ds = static_cast<d*>(pB_D);      pD_Ds->g();      //B2* pB2_Ds = static_cast<b2*>(pB_D); //error, 不能转换为兄弟类   /*重新解释转型*/   struct rA int m_a; ; struct rB int m_b; ; struct rC : public rA, public rB ;   void CastReinterpret (void)     int *i= new int;     *i = 10;     std::cout << *i =  << *i << std::endl;     std::cout << i =  << i << std::endl;     double *d=reinterpret_cast<double*> (i);     std::cout << *d =  << *d << std::endl;     std::cout << d =  << d << std::endl;       rC c;     std::cout << &c =  << &c << std::endl             << reinterpret_cast<rb*>(&c) =  <<reinterpret_cast<rb*>(&c) << std::endl             << static_cast <rb*>(&c) =  << static_cast <rb*>(&c) << std::endl             << reinterpret_cast<ra*>(&c) =  <<reinterpret_cast<ra*>(&c) << std::endl             << static_cast <ra*>(&c) =  << static_cast <ra*>(&c) << std::endl             << std::endl;   int main (void)     std::cout << std::endl << 常量性转除: << std::endl;     CastConst();     std::cout << std::endl << 安全向下转型: << std::endl;     CastDynamic();     std::cout << std::endl << 重新解释转型: << std::endl;     CastReinterpret(); </ra*></ra*></reinterpret_cast<ra*></ra*></rb*></rb*></reinterpret_cast<rb*></rb*></double*></b2*></d*></b2*></d*></s&></s*></iostream>

 

输出:

 

 

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常量性转除: s.value = 0 s.value = 1 s.value = 2   安全向下转型: Derived::f Derived::g Derived::g Derived::g   重新解释转型: *i = 10 i = 0x471718 *d = 2.55917e-307 d = 0x471718 &c = 0x22feb0 reinterpret_cast<rb*>(&c) = 0x22feb0 static_cast <rb*>(&c) = 0x22feb4 reinterpret_cast<ra*>(&c) = 0x22feb0 static_cast <ra*>(&c) = 0x22feb0 </ra*></ra*></rb*></rb*>

 

 

https://www.cnblogs.com/daocaorenblog/p/5279077.html