Python按value取字典中的top3

Posted 2021-02-13 eric20180814

n = 3
data = {‘John‘: 100, ‘Erica‘: 40, ‘Make‘:65, ‘Tom‘: 80}
print(data)
temp_list = sorted(data.items(), key= lambda item:item[1], reverse= True)
top3_list = temp_list[: n]
print(top3_list)
top3_dict = {}
for l in top3_list:
    top3_dict[l[0]] = l[1]
print(top3_dict)

结果为：

{‘John‘: 100, ‘Erica‘: 40, ‘Make‘: 65, ‘Tom‘: 80}
[(‘John‘, 100), (‘Tom‘, 80), (‘Make‘, 65)]
{‘John‘: 100, ‘Tom‘: 80, ‘Make‘: 65}

参考自：https://blog.csdn.net/u014662865/article/details/81807112