python实现寻找目录中最新的文件

Posted 2021-02-09 哈希哥

具体代码如下

class lastfile(object):
    #将测试报告全部收集到list中
    def listdir(self,path, filelist):  # 传入存储的list
        for file in os.listdir(path):
            file_path = os.path.join(path, file)
            if os.path.isdir(file_path):
                self.listdir(file_path, filelist)
            else:
                filelist.append((file_path, os.path.getctime(file_path)))
    #找最近的测试报告
    def newestfile(self,target_list):  #target_list  <class ‘list‘>: [(‘D:/pyworkspace/MMSAutoTest/case_and_report/DataReport20190124 143550.xlsx‘, 1548311750.7006826), (‘D:/pyworkspace/MMSAutoTest/case_and_report/DataReport20190124 144627.xlsx‘, 1548312387.9881263), (‘D:/pyworkspace/MMSAutoTest/case_and_report/mmscase.xlsx‘, 1548054043.7202337)]
        newest_file = target_list[0]
        for i in range(len(target_list)):
            if i < (len(target_list) - 1) and newest_file[1] < target_list[i + 1][1]:
                newest_file = target_list[i + 1]
            else:
                continue
        return newest_file