python多线程实现预测饭局组织者

Posted 2021-02-02 jason89

 1 from threading import Thread
 2 import random
 3 import time
 4 def get_organizers():
 5     ‘‘‘获取组局者‘‘‘
 6     count = len(name_lists)
 7     num = random.randint(0,count-1)
 8     organizer = name_lists[num]
 9     print(‘组局者是：%s‘ % (organizer,))
10     name_lists.pop(num)  # 将组局者从列表中删除
11 
12 def get_participants():
13     ‘‘‘获取参者‘‘‘
14     time.sleep(0.5) # 设置休眠时间，单位是秒
15     print(‘参与者是:‘ , name_lists)
16 
17 if __name__ == "__main__":
18     name_lists = [‘搜狐董事长张朝阳‘,‘小米CEO雷军‘,‘新美大CEO王‘,‘华为高级副总裁余承东‘,‘百度总裁张亚勤‘,‘360董事长周鸿祎‘,
19                   ‘微软全球执行副总裁沈向洋‘,‘联想CEO杨元庆‘,‘红杉资本全球执行合伙人沈南鹏‘,‘宽带资本董事长田溯宁‘,
20                   ‘京东CEO刘强东‘,‘爱奇艺CEO龚宇‘,‘滴滴出行CEO程维‘,‘58同城CEO姚劲波‘,‘高瓴资本张磊‘]
21     t1 = Thread(target=get_organizers)   # 创建线程1
22     t2 = Thread(target=get_participants) # 创建线程2
23     t1.start() # 开启线程1
24     t2.start() # 开启线程2
25     t1.join()  # 等待线程1结束
26     t2.join()  # 等待线程2结束