[LeetCode&Python] Problem 543. Diameter of Binary Tree

Posted 2021-01-25 chiyeung

Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.

Example:
Given a binary tree 

          1
         /         2   3
       /      
      4   5    

 

Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].

Note: The length of path between two nodes is represented by the number of edges between them.

 

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    def diameterOfBinaryTree(self, root):
        """
        :type root: TreeNode
        :rtype: int
        """
        self.ans=1
        def dfs(node):
            if not node:
                return 0
            L=dfs(node.left)
            R=dfs(node.right)
            self.ans=max(self.ans,L+R+1)
            return max(L,R)+1
        dfs(root)
        return self.ans-1