python 矩阵转置

Posted 2021-01-22 F

 

arrA=[[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16]]
N=4
#声明4x4数组arr
arrB=[[None] * N for row in range(N)]

print(‘[原设置的矩阵内容]‘)
for i in range(4):
    for j in range(4):
        print(‘%d‘ %arrA[i][j],end=‘	‘)
    print()

#进行矩阵转置的操作
for i in range(4):
    for j in range(4):
        arrB[i][j]=arrA[j][i]
    
print(‘[转置矩阵的内容为]‘)
for i in range(4):
    for j in range(4):
        print(‘%d‘ %arrB[i][j],end=‘	‘)
    print()

输出

[原设置的矩阵内容]
1    2    3    4    
5    6    7    8    
9    10    11    12    
13    14    15    16    
[转置矩阵的内容为]
1    5    9    13    
2    6    10    14    
3    7    11    15    
4    8    12    16