1python三级菜单，小白第一次随笔

Posted 2021-01-21 yangyang---1

#----------第三级菜单，进入后，随便输入就会退出到第三级菜单，是不是有点问题------------
data = {
    ‘北京‘:{
        "昌平":{
            "沙河":["oldboy","test"],
            "天通苑":["链家地产","我爱我家"]
        },
        "朝阳":{
            "望京":["奔驰","陌陌"],
            "国贸":["CICC","HP"],
            "东直门":["Advent","飞信"],
        },
        "海淀":{},
    },
    ‘山东‘:{
        "德州":{},
        "青岛":{},
        "济南":{}
    },
    ‘广东‘:{
        "东莞":{},
        "常熟":{},
        "佛山":{},
    },
}

exit_flag = False

while not exit_flag:
    for i in data:
        print(i)
    chioes = input(‘输入一级菜单名称：‘)
    if chioes in data:
        while not exit_flag:
            for i2 in data[chioes]:
                print(‘	‘,i2)
            chioes2 = input(‘请输入二级菜单：‘)
            if chioes2 in data[chioes]:
                while  not exit_flag:
                    for i3 in data[chioes][chioes2]:
                        print(‘		‘,i3)
                    chioes3 = input(‘请输入三级菜单：‘)
                    if chioes3 in data[chioes][chioes2]:
                        for i4 in  data[chioes][chioes2][chioes3]:
                            print(‘			‘,i4)
                        chioes4 = input(‘返回上一层请输入b，退出请输入q‘)
                        if chioes4 == ‘b‘:
                            pass #占位符没有意思直接略过，执行if chioes3 in data[chioes][chioes2]
                        elif chioes4 == ‘q‘:
                            exit_flag = True
                    if chioes3 == ‘b‘ :
                        break
                    elif chioes3 == ‘q‘:
                        exit_flag = True
            if chioes2 == ‘b‘:
                break
            elif chioes2 == ‘q‘:
                exit_flag = True
    if chioes == ‘b‘:
         break