求一个数组中最接近平均值的数,用java编程

Posted 2023-05-15

求一个数组中最接近平均值的数,用java编程

参考技术A         double[] arr = new double[10];
        double sum = 0;

        for (int i = 0; i < arr.length; i++) 
            arr[i] = Math.random();
            sum += arr[i];
        

        double average = sum / arr.length;
        Arrays.sort(arr);

        int i = Arrays.binarySearch(arr, average);

        if (i < 0) 
            i = -i - 1;
            if (arr[i] - average > average - arr[i - 1]) 
                i--;
            
        
        
        System.out.println("所求的值：" + arr[i]);

参考技术B System.out.println("舍掉小数取整:Math.floor(2)=" + (int)Math.floor(i));

用java script 求数组的最大值最小值和平均数

let readline = require(`readline-sync`);

console.log(`请输入数组的长度`);

let long = ~~readline.question(``);

let arr = [];

let sum = 0;

let average = 0;

for (let i = 0; i < long; i++) {

console.log(`请输入第` + (i + 1) + `项的值：`);

arr[i] = parseFloat(readline.question(``));

sum += arr[i];

average = parseFloat(sum / 2);

}

console.log(`请选择要执行的操作：1.求最大值 2.求最小值 3.求和 4.求平均数`);

let num = ~~readline.question(``);

arr.sort(function (j, k) { return j - k; });

if (num === 1) {

console.log(`最大值为：` + arr[arr.length - 1]);

} else if (num === 2) {

console.log(`最小值为：` + arr[0]);

}

else if (num === 3) {

console.log(`求和的值为：` + sum);

} else if (num === 4) {

console.log(`平均值为：` + average);

}