Java代码实现：查找list中的数字与目标数最接近的数，打印出来，急求？

Posted 2023-03-09

参考技术A public static void main(String args[])
int target = 584;
ArrayList<String> array = new ArrayList<String>();
String string = "wodf125bbsdfa36sfgsfd580";
Pattern pattern = Pattern.compile("\\d+");
Matcher matcher = pattern.matcher(string);
while(matcher.find())
array.add(matcher.group());

int need = Integer.valueOf(array.toArray()[0].toString());
int frag = Math.abs(need- target);

for(int i = 0; i< array.size(); i++)
int temp = Math.abs(Integer.valueOf(array.toArray()[i].toString()) - target);
if(temp < frag)
frag = temp;
need = Integer.valueOf(array.toArray()[i].toString());


System.out.println("need="+need);
参考技术B List<Integer> list = new ArrayList<Integer>();
for (int i = 0; i < 10; i++)

list.add(i);

// 接近的数字
int nearNum = 6;
// 差值实始化
int diffNum = Math.abs(list.get(0) - nearNum);
// 最终结果
int result = list.get(0);
for (Integer integer : list)

int diffNumTemp = Math.abs(integer - nearNum);
if (diffNumTemp < diffNum)

diffNum = diffNumTemp;
result = integer;


System.out.println(result);本回答被提问者和网友采纳