Python线程同步
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线程执行
join与setDaemon
子线程在主线程运行结束后,会继续执行完,如果给子线程设置为守护线程(setDaemon=True),主线程运行结束子线程即结束;
如果join()线程,那么主线程会等待子线程执行完再执行。
1 import threading
2 import time
3
4
5 def get_thread_a():
6 print("get thread A started")
7 time.sleep(3)
8 print("get thread A end")
9
10
11 def get_thread_b():
12 print("get thread B started")
13 time.sleep(5)
14 print("get thread B end")
15
16
17 if __name__ == "__main__":
18 thread_a = threading.Thread(target=get_thread_a)
19 thread_b = threading.Thread(target=get_thread_b)
20 start_time = time.time()
21 thread_b.setDaemon(True)
22 thread_a.start()
23 thread_b.start()
24 thread_a.join()
25
26 end_time = time.time()
27 print("execution time: {}".format(end_time - start_time))
thread_a是join,首先子线程thread_a执行,thread_b是守护线程,当主线程执行完后,thread_b不会再执行
执行结果如下:
get thread A started
get thread B started
get thread A end
execution time: 3.003199815750122
线程同步
当线程间共享全局变量,多个线程对该变量执行不同的操作时,该变量最终的结果可能是不确定的(每次线程执行后的结果不同),如:对count变量执行加减操作 ,count的值是不确定的,要想count的值是一个确定的需对线程执行的代码段加锁。
python对线程加锁主要有Lock和Rlock模块
Lock:
from threading import Lock
lock = Lock()
lock.acquire()
lock.release()
Lock有acquire()和release()方法,这两个方法必须是成对出现的,acquire()后面必须release()后才能再acquire(),否则会造成死锁
Rlock:
鉴于Lock可能会造成死锁的情况,RLock(可重入锁)对Lock进行了改进,RLock可以在同一个线程里面连续调用多次acquire(),但必须再执行相同次数的release()
from threading import RLock
lock = RLock()
lock.acquire()
lock.acquire()
lock.release()
lock.release()
condition(条件变量),线程在执行时,当满足了特定的条件后,才可以访问相关的数据
import threading
def get_thread_a(condition):
with condition:
condition.wait()
print("A : Hello B,that\'s ok")
condition.notify()
condition.wait()
print("A : I\'m fine,and you?")
condition.notify()
condition.wait()
print("A : Nice to meet you")
condition.notify()
condition.wait()
print("A : That\'s all for today")
condition.notify()
def get_thread_b(condition):
with condition:
print("B : Hi A, Let\'s start the conversation")
condition.notify()
condition.wait()
print("B : How are you")
condition.notify()
condition.wait()
print("B : I\'m fine too")
condition.notify()
condition.wait()
print("B : Nice to meet you,too")
condition.notify()
condition.wait()
print("B : Oh,goodbye")
if __name__ == "__main__":
condition = threading.Condition()
thread_a = threading.Thread(target=get_thread_a, args=(condition,))
thread_b = threading.Thread(target=get_thread_b, args=(condition,))
thread_a.start()
thread_b.start()
Condition内部有一把锁,默认是RLock,在调用wait()和notify()之前必须先调用acquire()获取这个锁,才能继续执行;当wait()和notify()执行完后,需调用release()释放这个锁,在执行with condition时,会先执行acquire(),with结束时,执行了release();所以condition有两层锁,最底层锁在调用wait()时会释放,同时会加一把锁到等待队列,等待notify()唤醒释放锁
wait() :允许等待某个条件变量的通知,notify()可唤醒
notify(): 唤醒等待队列wait()
执行结果:
B : Hi A, Let\'s start the conversation
A : Hello B,that\'s ok
B : How are you
A : I\'m fine,and you?
B : I\'m fine too
A : Nice to meet you
B : Nice to meet you,too
A : That\'s all for today
B : Oh,goodbye
Semaphore(信号量)
用于控制线程的并发数,如爬虫中请求次数过于频繁会被禁止ip,每次控制爬取网页的线程数量可在一定程度上防止ip被禁;文件读写中,控制写线程每次只有一个,读线程可多个。
import time
import threading
def get_thread_a(semaphore,i):
time.sleep(1)
print("get thread : {}".format(i))
semaphore.release()
def get_thread_b(semaphore):
for i in range(10):
semaphore.acquire()
thread_a = threading.Thread(target=get_thread_a, args=(semaphore,i))
thread_a.start()
if __name__ == "__main__":
semaphore = threading.Semaphore(2)
thread_b = threading.Thread(target=get_thread_b, args=(semaphore,))
thread_b.start()
上述示例了每隔1秒并发两个线程执行的情况,当调用一次semaphore.acquire()时,Semaphore的数量就减1,直至Semaphore数量为0时被锁上,当release()后Semaphore数量加1。Semaphore在本质上是调用的Condition,semaphore.acquire()在Semaphore的值为0的条件下会调用Condition.wait(), 否则将值减1,semaphore.release()会将Semaphore的值加1,并调用Condition.notify()
Semaphore源码
def acquire(self, blocking=True, timeout=None):
if not blocking and timeout is not None:
raise ValueError("can\'t specify timeout for non-blocking acquire")
rc = False
endtime = None
with self._cond:
while self._value == 0:
if not blocking:
break
if timeout is not None:
if endtime is None:
endtime = _time() + timeout
else:
timeout = endtime - _time()
if timeout <= 0:
break
self._cond.wait(timeout)
else:
self._value -= 1
rc = True
return rc
def release(self):
with self._cond:
self._value += 1
self._cond.notify()
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