674. Longest Continuous Increasing Subsequence@python

Posted 2021-01-09 Chim

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it‘s not a continuous one where 5 and 7 are separated by 4.

题目地址: Longest Continuous Increasing Subsequence

难度: Easy

题意: 找出呈递增的趋势的子数组,返回最大长度

思路:

遍历数组,并计数,比较简单

class Solution(object):
    def findLengthOfLCIS(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        n = len(nums)
        if n <= 1:
            return len(nums)
        
        res = 0
        length = 1
        for i in range(n-1):
            if nums[i] < nums[i+1]:
                length += 1
            else:
                res = max(length, res)
                length = 1
        res = max(length, res)  
        return res

时间复杂度: O(n)

空间复杂度: O(1)