717. 1-bit and 2-bit Characters@python
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We have two special characters. The first character can be represented by one bit 0
. The second character can be represented by two bits (10
or 11
).
Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.
Example 1:
Input: bits = [1, 0, 0] Output: True Explanation: The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.
原题地址: 1-bit and 2-bit Characters
难度: Easy
题意: 存在两类数,一类是10或者11,另一类为0.将一个数组拆分为这两类数,判断最后一组数为0,比如上面例子,第一组数为[1,0],第二组数为[0]
思路:
对于数字1,后面的一个数字是1或者0都行,所以遇到以可以跳过1后面的值,遇到0,则移动一位
代码:
class Solution(object): def isOneBitCharacter(self, bits): """ :type bits: List[int] :rtype: bool """ i = 0 while i < len(bits): if bits[i] == 1: i += 2 if i == len(bits): return False else: i += 1 return True
时间复杂度: O(n)
空间复杂度: O(1)
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