[LeetCode&Python] Problem 561. Array Partition I
Posted chiyeung
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了[LeetCode&Python] Problem 561. Array Partition I相关的知识,希望对你有一定的参考价值。
Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.
Example 1:
Input: [1,4,3,2] Output: 4 Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).
Note:
- n is a positive integer, which is in the range of [1, 10000].
- All the integers in the array will be in the range of [-10000, 10000].
My method:
Step 1: sort the list L
Step 2: sum(L[0]+L[2]+L[4]+...+L[2n-2])
Code:
class Solution: def arrayPairSum(self, nums): """ :type nums: List[int] :rtype: int """ nums=sorted(nums) return sum(nums)-sum(nums[::-2])
以上是关于[LeetCode&Python] Problem 561. Array Partition I的主要内容,如果未能解决你的问题,请参考以下文章
C++&Python描述 LeetCode C++&Python描述 LeetCode 剑指 Offer 22. 链表中倒数第k个节点
[LeetCode&Python] Problem 202. Happy Number
[LeetCode&Python] Problem 520. Detect Capital
[LeetCode&Python] Problem 383. Ransom Note