python的第九天

Posted 2021-01-06 拐弯

‘‘‘2，写函数，检查获取传入列表或元组对象的所有奇数位索引对应的元素，并将其作为新列表返回给调用者。‘‘‘
def jishu(lis):
    lis1 = []
    for i in range(len(lis)):
        if i % 2 == 1:
            lis1.append(lis[i])
    return lis1
lis = [1,2,3,4,5,6,7,8,9,10]
lis1 = jishu(lis)
print(lis1)
‘‘‘3，写函数，判断用户传入的对象（字符串、列表、元组）长度是否大于5。‘‘‘
def len_1(s):
    if len(s) > 5:
        return True
    else:
        return False
s = "46assd"
if len_1(s):
    print("长度大于5")
else:
    print("长度小于5")
‘‘‘4，写函数，检查传入列表的长度，如果大于2，将列表的前两项内容返回给调用者。‘‘‘
def len_2(s):
    if len(s) > 2:
        return [s[0], s[1]]
    else:
        return s
lis = [3,5,9,6,8]
lis1 = len_2(lis)
print(lis1)

def len_2(s):
    if len(s) > 2:
        if type(s) == str:
            return s[:2]
        elif type(s) == dict:
            dic = {}
            count = 0
            for k, v in dict.items(s):
                count += 1
                dic.setdefault(k, v)
                if count == 2:
                    return dic
        else:
            return s[0], s[1]
    else:
        return False
dic = [5,8,9,10]
s = len_2(dic)
print(s)
‘‘‘5，写函数，计算传入函数的字符串中, 数字、字母、空格 以及 其他内容的个数，并返回结果。‘‘‘
def count(s):
    num = 0
    letter = 0
    kg = 0
    qit = 0
    for i in str(s):
        if i.isdigit():
            num += 1
        elif i.islower() or i.isupper():
            letter += 1
        elif i == " ":
            kg += 1
        else:
            qit += 1
    return "数字:%s 字母:%s 空格:%s 其他内容:%s" % (num, letter, kg, qit)
st = "123 as d   ‘‘‘"
stt = count(st)
print(stt)
‘‘‘6，写函数，接收两个数字参数，返回比较大的那个数字。‘‘‘
def up(a, b):
    if type(a) == int and type(b) == int:
        if a < b:
            return b
        else:
            return a
    else:
        return False
a = up(10,8)
print(a)

‘‘‘7，写函数，检查传入字典的每一个value的长度,如果大于2，那么仅保留前两个长度的内容，并将新内容返回给调用者。‘‘‘
‘‘‘    dic = {"k1": "v1v1", "k2": [11,22,33,44]}
   PS:字典中的value只能是字符串或列表
‘‘‘
def dic2(s):
    dic1 = {}
    for k, v in dict.items(s):
        if type(v) == str and len(v) > 2:
            dic1[k] = v[:2]
        elif type(v) == list and len(v) > 2:
            dic1[k] = [v[0], v[1]]
            # print(v[0], v[1])
        else:
            dic1[k] = v
    return dic1
dic = {"k1": "v1v1", "k2": [11,22,33,44]}
dic1 = dic2(dic)
print(dic1)

def dic2(s):
    dic = {}
    for k, v in dict.items(s):
        if type(v) == int:
            st = str(v)
            dic.setdefault(k, int(st[:2]))
        elif len(v) > 2:
            if type(v) == str:
                dic.setdefault(k, v[:2])
            elif type(v) == dict:
                count = 0
                dic1 = {}
                for k, v in dict.items(v):
                    count += 1
                    dic1.setdefault(k, v)
                    if count == 2:
                        break
                dic.setdefault(k, dic1)
            elif type(v) == list:
                lis = [v[0], v[1]]
                dic.setdefault(k, lis)
    return dic
dic1 = {1:"asdas", 2:[1,2,3,4], 3:45644, 4:{3:3,4:5,6:7}}
ll = dic2(dic1)
print(ll)

‘‘‘
8，写函数，此函数只接收一个参数且此参数必须是列表数据类型，
此函数完成的功能是返回给调用者一个字典，
此字典的键值对为此列表的索引及对应的元素。
例如传入的列表为：[11,22,33] 返回的字典为 {0:11,1:22,2:33}。
‘‘‘
def dic(s):
    dic1 = {}
    for i in range(len(s)):
        dic1.setdefault(i, s[i])
    return dic1
lis = [1,2,3,4,4]
dic1 = dic(lis)
print(dic1)
‘‘‘
9，写函数，函数接收四个参数分别是：姓名，性别，年龄，学历。
用户通过输入这四个内容，然后将这四个内容传入到函数中，
此函数接收到这四个内容，将内容追加到一个student_msg文件中。                                  
‘‘‘
def peop(name, sex, age, xue):
    with open("student_msg", mode=‘a‘, encoding="utf-8") as f:
        f.write("姓名:"+name+"	")
        f.write("性别:"+sex+"	")
        f.write("年龄:"+age+"	")
        f.write("学历:"+xue+"	")
peop("张紫益", "男", "29", "中专")

‘‘‘10，对第9题升级：支持用户持续输入，Q或者q退出，性别默认为男，如果遇到女学生，则把性别输入女。‘‘‘
def peo(name, sex, xue, age="男"):
    with open("student_msg", mode=‘a‘, encoding="utf-8") as f:
        f.write("
"+name+"	"+sex+"	"+age+"	"+xue+"	")
def pd():
    pd = input("输入Q q 退出:").strip()
    if pd.upper() == "Q":
        return True
    else:
        return False

while 1:
    name = input("请输入姓名:").strip()
    age = input("请输入年龄:").strip()
    xue = input("请输入学历:").strip()
    sex = input("请输入性别:").strip()
    if sex == "":
        peo(name, age, xue)
        if pd():
            break
    else:
        peo(name, age, xue, sex)
    if pd():
        break
‘‘‘11，写函数，用户传入修改的文件名，与要修改的内容，执行函数，完成整个文件的批量修改操作（升级题）。‘‘‘
def gai(name, loor, new ):
    import os
    name1 = name+"a"
    with open(name, mode="r", encoding="utf-8") as f1,
            open(name1, mode="w", encoding="utf-8") as f2:
        for line in f1:
            st = line.replace(loor, new)
            f2.write(st)
    os.remove(name)
    os.rename(name1, name)
gai("student_msg","女","男")

‘‘‘12，写一个函数完成三次登陆功能，再写一个函数完成注册功能(升级题)‘‘‘
def zhuce():
    print("请完成注册!")
    name = input("用户名:").strip()
    password = input("密码") .strip()
    with open("xinxi", mode=‘a‘, encoding="utf-8")as f:
        f.write(name+"	"+password+"
")
    print("注册成功!  账号:%s  密码:%s" % (name, password))
def denglu():
    count = 3
    while count > 0:
        count -= 1
        name = input("请输入用户名:").strip()
        password = input("请输入密码") .strip()
        with open("xinxi", mode=‘r‘, encoding="utf-8") as f:
            for line in f:
                lis = line.split()
                if lis[0] == name and lis[1] == password:
                    return True
            else:
                print("密码错误!您还有%s 次机会!" % count)
    return False
while 1:
    print("注册: 1 登录: 2 退出: Q")
    num = input("请输入:").strip()
    if num.upper() == "Q":
        break
    elif num == "1":
        zhuce()
    elif num == "2":
        if denglu():
            print("登录成功!")
            break
        else:
            print("登录失败!")
    else:
        print("输入错误! 重新输入!")