如何用Python os.path.walk方法遍历搜索文件内容的操作详解

Posted 2023-05-10

参考技术A 本文是关于如何用Python os.path.walk方法遍历搜索文件目录内容的操作详解的文章，python 代码中用os.path.walk函数这个python模块的方法来遍历文件，python列出文件夹下的所有文件并找到自己想要的内容。
文中使用到了Python os模块和Python sys模块，这两个模块具体的使用方法请参考玩蛇网相关文章阅读。
Python os.path.walk方法遍历文件搜索内容方法代码如下：
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import os, sys#代码中需要用到的方法模块导入 listonly = False skipexts = ['.gif', '.exe', '.pyc', '.o', '.a','.dll','.lib','.pdb','.mdb'] # ignore binary files def visitfile(fname, searchKey): global fcount, vcount try: if not listonly: if os.path.splitext(fname)[1] in skipexts: pass elif open(fname).read().find(searchKey) != -1: print'%s has %s' % (fname, searchKey) fcount += 1 except: pass vcount += 1 #www.iplaypy.com def visitor(args, directoryName,filesInDirectory): for fname in filesInDirectory: fpath = os.path.join(directoryName, fname) if not os.path.isdir(fpath): visitfile(fpath,args) def searcher(startdir, searchkey): global fcount, vcount fcount = vcount = 0 os.path.walk(startdir, visitor, searchkey) if __name__ == '__main__': root=raw_input("type root directory:") key=raw_input("type key:") searcher(root,key) print 'Found in %d files, visited %d' % (fcount, vcount)

如何用python get方法 获取里面的所有相同标签后的数据？

打开如下
"code":"10000","msg":"success","date":"2022-09-08","data":[
"id":"1","idNO":83,"ders":"A1",
"id":"2","idNO":30,"ders":"A2",
"id":"3","idNO":75,"ders":"A3"]

要求取出这三个大括号 内idNO 后面的数据, 分别给变量A,B,C

代码如下
url="https://test.com/tests"
no1 = urllib.request.urlopen(url).read()
no1_dict = json.loads(no1)
test=no1_dict.get('data', [])
接下去要怎么写 请指教

参考技术A

代码

输出

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