Python super初始化理解过程

Posted 2021-01-03

# -*- coding：utf-8 -*-<br data-filtered="filtered">
class A(object):
    def __init__(self, xing, gender):          # ！#1
        self.namea = "aaa"                     # ！#2
        self.xing = xing                       # ！#3
        self.gender = gender                   # ！#4
        self.funca()

    def funca(self):
        print("function a : %s" % self.namea)


class B(A):
    def __init__(self, xing, age):             # ！#5
        super(B, self).__init__(xing, age)     # ！#6（age处应为gender）
        self.nameb = "bbb"                     # ！#7
        ##self.namea="ccc"                     # ！#8
        ##self.xing = xing.upper()             # ！#9
        self.age = age                         # ！#10

    def funcb(self):
        print("function b : %s" % self.nameb)

    def funca(self):
        print("(override)function a : %s" % self.namea)


b = B("lin", 22)                               # ！#11
print(b.nameb)
print(b.namea)
print(b.xing)                                  # ！#12
print(b.age)
print(b.gender)                                # ！#13
b.funcb()
b.funca()

　　上面程序的输出结果为：

(override)function a : aaa
bbb
aaa
lin
22
22
function b : bbb
(override)function a : aaa

　　以上程序说明如果父类初始化方法中有调用了父类中定义的方法，恰好这个方法又被子类所覆盖，则super(B, self).__init__(xing, age)调用的父类初始化方法中调用的方法将是被覆盖后的方法。