Python开发第二篇运算符
Posted Tanglaoer
tags:
篇首语：本文由小常识网(cha138.com)小编为大家整理，主要介绍了Python开发第二篇运算符相关的知识，希望对你有一定的参考价值。
"+" 加号
__author__ = ‘Tang‘ a = 8 b = 9 c = a + b print(c) # 17 a = 8.0 b = 9 c = a + b print(c) # 17.0 a = 8 b = 9.0 c = a + b print(c) # 17.0
“-” 减号
__author__ = ‘Tang‘ # 正数 a = 9 b = 8 c = a - b print(c) # 1 a = 9.0 b = 8 c = a - b print(c) # 1.0 a = 9 b = 8.0 c = a - b print(c) # 1.0 # 负数 a = 8 b = 9 c = a - b print(c) # -1 a = 8.0 b = 9 c = a - b print(c) # -1.0 a = 8 b = 9.0 c = a - b print(c) # -1.0
"*" 乘号
__author__ = ‘Tang‘ a = 9 b = 8 c = a * b print(c) # 72 a = 9.0 b = 8 c = a * b print(c) # 72.0 a = 9 b = 8.0 c = a * b print(c) # 72.0
"/" 除号
__author__ = ‘Tang‘ a = 9 b = 3 c = a / b print(c) # 3.0 a = 9.0 b = 3 c = a / b print(c) # 3.0 a = 9 b = 3.0 c = a / b print(c) # 3.0 a = 9 b = 8 c = a / b print(c) # 1.125 a = 9.0 b = 8 c = a / b print(c) # 1.125 a = 9 b = 8.0 c = a / b print(c) # 1.125
"%" 求余
__author__ = ‘Tang‘
a = 9
b = 3
c = a % b
print(c) # 0
a = 9.0
b = 3
c = a % b
print(c) # 0.0
a = 9
b = 3.0
c = a % b
print(c) # 0.0
a = 9
b = 8
c = a % b
print(c) # 1
a = 9.0
b = 8
c = a % b
print(c) # 1.0
a = 9
b = 8.0
c = a % b
print(c) # 1.0
"**" 次方
__author__ = ‘Tang‘ a = 9 b = 3 c = a ** b print(c) # 729 a = 9.0 b = 3 c = a ** b print(c) # 729.0 a = 9 b = 3.0 c = a ** b print(c) # 729.0
"//" 取整
__author__ = ‘Tang‘ a = 9 b = 3 c = a // b print(c) # 3 a = 9.0 b = 3 c = a // b print(c) # 3.0 a = 9 b = 3.0 c = a // b print(c) # 3.0 a = 5 b = 2 c = a // b print(c) # 2 a = 5.0 b = 2 c = a // b print(c) # 2.0 a = 5 b = 2.0 c = a // b print(c) # 2.0
以上是关于Python开发第二篇运算符的主要内容，如果未能解决你的问题，请参考以下文章