求c语言下获取一个字符串MD5值得函数

Posted 2023-05-08

如题

参考技术A 1. md5.h：

＃pragma once

typedef unsigned long int UINT32;
typedef unsigned short int UINT16;

/× MD5 context. */
typedef struct
UINT32 state[4]; /× state (ABCD) */
UINT32 count[2]; /× number of bits, modulo 2^64 (lsb first) */
unsigned char buffer[64]; /× input buffer */
MD5_CTX;

void MD5Init (MD5_CTX *);
void MD5Update (MD5_CTX *, unsigned char *, unsigned int);
void MD5Final (unsigned char [16], MD5_CTX *);

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2. md5.cpp：

＃include "md5.h"

＃include "memory.h"

＃define S11 7
＃define S12 12
＃define S13 17
＃define S14 22
＃define S21 5
＃define S22 9
＃define S23 14
＃define S24 20
＃define S31 4
＃define S32 11
＃define S33 16
＃define S34 23
＃define S41 6
＃define S42 10
＃define S43 15
＃define S44 21

static void MD5Transform (UINT32 a[4], unsigned char b[64]);
static void Encode (unsigned char *, UINT32 *, unsigned int);
static void Decode (UINT32 *, unsigned char *, unsigned int);

static unsigned char PADDING[64] =
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
;

＃define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
＃define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
＃define H(x, y, z) ((x) ^ (y) ^ (z))
＃define I(x, y, z) ((y) ^ ((x) | (~z)))

＃define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n))))

＃define FF(a, b, c, d, x, s, ac)
(a) += F ((b), (c), (d)) + (x) + (UINT32)(ac);
(a) = ROTATE_LEFT ((a), (s));
(a) += (b);

＃define GG(a, b, c, d, x, s, ac)
(a) += G ((b), (c), (d)) + (x) + (UINT32)(ac);
(a) = ROTATE_LEFT ((a), (s));
(a) += (b);

＃define HH(a, b, c, d, x, s, ac)
(a) += H ((b), (c), (d)) + (x) + (UINT32)(ac);
(a) = ROTATE_LEFT ((a), (s));
(a) += (b);

＃define II(a, b, c, d, x, s, ac)
(a) += I ((b), (c), (d)) + (x) + (UINT32)(ac);
(a) = ROTATE_LEFT ((a), (s));
(a) += (b);


void MD5Init (MD5_CTX *context)

context->count[0] = context->count[1] = 0;

context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;


void MD5Update (MD5_CTX *context, unsigned char *input, unsigned int inputLen)

unsigned int i, index, partLen;

index = (unsigned int)((context->count[0] >> 3) & 0x3F);

if ((context->count[0] += ((UINT32)inputLen << 3))
< ((UINT32)inputLen << 3))
context->count[1]++;
context->count[1] += ((UINT32)inputLen >> 29);

partLen = 64 - index;

if (inputLen >= partLen)
memcpy((unsigned char *)&context->buffer[index], (unsigned char *)input, partLen);
MD5Transform (context->state, context->buffer);

for (i = partLen; i + 63 < inputLen; i += 64)
MD5Transform (context->state, &input[i]);

index = 0;

else
i = 0;

memcpy((unsigned char *)&context->buffer[index], (unsigned char *)&input[i],
inputLen-i);


void MD5Final (unsigned char digest[16], MD5_CTX * context)

unsigned char bits[8];
unsigned int index, padLen;

Encode (bits, context->count, 8);

index = (unsigned int)((context->count[0] >> 3) & 0x3f);
padLen = (index < 56) ? (56 - index) : (120 - index);
MD5Update (context, PADDING, padLen);

MD5Update (context, bits, 8);

Encode (digest, context->state, 16);

memset ((unsigned char *)context, 0, sizeof (*context));


static void MD5Transform (UINT32 state[4], unsigned char block[64])

UINT32 a = state[0], b = state[1], c = state[2], d = state[3], x[16];

Decode (x, block, 64);

/× Round 1 */
FF (a, b, c, d, x[ 0], S11, 0xd76aa478); /× 1 */
FF (d, a, b, c, x[ 1], S12, 0xe8c7b756); /× 2 */
FF (c, d, a, b, x[ 2], S13, 0x242070db); /× 3 */
FF (b, c, d, a, x[ 3], S14, 0xc1bdceee); /× 4 */
FF (a, b, c, d, x[ 4], S11, 0xf57c0faf); /× 5 */
FF (d, a, b, c, x[ 5], S12, 0x4787c62a); /× 6 */
FF (c, d, a, b, x[ 6], S13, 0xa8304613); /× 7 */
FF (b, c, d, a, x[ 7], S14, 0xfd469501); /× 8 */
FF (a, b, c, d, x[ 8], S11, 0x698098d8); /× 9 */
FF (d, a, b, c, x[ 9], S12, 0x8b44f7af); /× 10 */
FF (c, d, a, b, x[10], S13, 0xffff5bb1); /× 11 */
FF (b, c, d, a, x[11], S14, 0x895cd7be); /× 12 */
FF (a, b, c, d, x[12], S11, 0x6b901122); /× 13 */
FF (d, a, b, c, x[13], S12, 0xfd987193); /× 14 */
FF (c, d, a, b, x[14], S13, 0xa679438e); /× 15 */
FF (b, c, d, a, x[15], S14, 0x49b40821); /× 16 */

/× Round 2 */
GG (a, b, c, d, x[ 1], S21, 0xf61e2562); /× 17 */
GG (d, a, b, c, x[ 6], S22, 0xc040b340); /× 18 */
GG (c, d, a, b, x[11], S23, 0x265e5a51); /× 19 */
GG (b, c, d, a, x[ 0], S24, 0xe9b6c7aa); /× 20 */
GG (a, b, c, d, x[ 5], S21, 0xd62f105d); /× 21 */
GG (d, a, b, c, x[10], S22, 0x2441453); /× 22 */
GG (c, d, a, b, x[15], S23, 0xd8a1e681); /× 23 */
GG (b, c, d, a, x[ 4], S24, 0xe7d3fbc8); /× 24 */
GG (a, b, c, d, x[ 9], S21, 0x21e1cde6); /× 25 */
GG (d, a, b, c, x[14], S22, 0xc33707d6); /× 26 */
GG (c, d, a, b, x[ 3], S23, 0xf4d50d87); /× 27 */
GG (b, c, d, a, x[ 8], S24, 0x455a14ed); /× 28 */
GG (a, b, c, d, x[13], S21, 0xa9e3e905); /× 29 */
GG (d, a, b, c, x[ 2], S22, 0xfcefa3f8); /× 30 */
GG (c, d, a, b, x[ 7], S23, 0x676f02d9); /× 31 */
GG (b, c, d, a, x[12], S24, 0x8d2a4c8a); /× 32 */

/× Round 3 */
HH (a, b, c, d, x[ 5], S31, 0xfffa3942); /× 33 */
HH (d, a, b, c, x[ 8], S32, 0x8771f681); /× 34 */
HH (c, d, a, b, x[11], S33, 0x6d9d6122); /× 35 */
HH (b, c, d, a, x[14], S34, 0xfde5380c); /× 36 */
HH (a, b, c, d, x[ 1], S31, 0xa4beea44); /× 37 */
HH (d, a, b, c, x[ 4], S32, 0x4bdecfa9); /× 38 */
HH (c, d, a, b, x[ 7], S33, 0xf6bb4b60); /× 39 */
HH (b, c, d, a, x[10], S34, 0xbebfbc70); /× 40 */
HH (a, b, c, d, x[13], S31, 0x289b7ec6); /× 41 */
HH (d, a, b, c, x[ 0], S32, 0xeaa127fa); /× 42 */
HH (c, d, a, b, x[ 3], S33, 0xd4ef3085); /× 43 */
HH (b, c, d, a, x[ 6], S34, 0x4881d05); /× 44 */
HH (a, b, c, d, x[ 9], S31, 0xd9d4d039); /× 45 */
HH (d, a, b, c, x[12], S32, 0xe6db99e5); /× 46 */
HH (c, d, a, b, x[15], S33, 0x1fa27cf8); /× 47 */
HH (b, c, d, a, x[ 2], S34, 0xc4ac5665); /× 48 */

/× Round 4 */
II (a, b, c, d, x[ 0], S41, 0xf4292244); /× 49 */
II (d, a, b, c, x[ 7], S42, 0x432aff97); /× 50 */
II (c, d, a, b, x[14], S43, 0xab9423a7); /× 51 */
II (b, c, d, a, x[ 5], S44, 0xfc93a039); /× 52 */
II (a, b, c, d, x[12], S41, 0x655b59c3); /× 53 */
II (d, a, b, c, x[ 3], S42, 0x8f0ccc92); /× 54 */
II (c, d, a, b, x[10], S43, 0xffeff47d); /× 55 */
II (b, c, d, a, x[ 1], S44, 0x85845dd1); /× 56 */
II (a, b, c, d, x[ 8], S41, 0x6fa87e4f); /× 57 */
II (d, a, b, c, x[15], S42, 0xfe2ce6e0); /× 58 */
II (c, d, a, b, x[ 6], S43, 0xa3014314); /× 59 */
II (b, c, d, a, x[13], S44, 0x4e0811a1); /× 60 */
II (a, b, c, d, x[ 4], S41, 0xf7537e82); /× 61 */
II (d, a, b, c, x[11], S42, 0xbd3af235); /× 62 */
II (c, d, a, b, x[ 2], S43, 0x2ad7d2bb); /× 63 */
II (b, c, d, a, x[ 9], S44, 0xeb86d391); /× 64 */

state[0] += a;
state[1] += b;
state[2] += c;
state[3] += d;

memset ((unsigned char *)x, 0, sizeof (x));


static void Encode (unsigned char *output, UINT32 *input, unsigned int len)

unsigned int i, j;

for (i = 0, j = 0; j < len; i++, j += 4)
output[j] = (unsigned char)(input[i] & 0xff);
output[j+1] = (unsigned char)((input[i] >> 8) & 0xff);
output[j+2] = (unsigned char)((input[i] >> 16) & 0xff);
output[j+3] = (unsigned char)((input[i] >> 24) & 0xff);



static void Decode (UINT32 *output, unsigned char *input, unsigned int len)

unsigned int i, j;

for (i = 0, j = 0; j < len; i++, j += 4)
output[i] = ((UINT32)input[j]) | (((UINT32)input[j+1]) << 8) |
(((UINT32)input[j+2]) << 16) | (((UINT32)input[j+3]) << 24);


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＃include <stdio.h>
＃include <string.h>

＃include "md5.h"

int main ()

char tmp[128];
unsigned char digest[16];

MD5_CTX context;

scanf("%s",tmp);

MD5Init (&context);
MD5Update (&context, (unsigned char*)tmp, strlen(tmp));
MD5Final (digest,&context);

printf("MD5Value:");
for(int i=0; i<16; ++i)

printf("%02X",digest[i]);

printf(" ");

return 0;

SQL 2000里面有没有语句把一个字符串用MD5加密

md5加密有相关的加密函数，但不是在数据库中操作的，数据库只是来保存加密的结果字符串。

加密的话你找相关语言的加密函数就行 参考技术A SQL 2008 有， 貌似SQL 2000 是没有的， Hashbytes('MD5',。。。。。