PTA练习题
Posted Lyh3012648079
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#include<iostream> using namespace std; class Time private: int hh; int mm; int ss; public: Time() hh = 0; mm = 0; ss = 0; void set(int h,int m,int s) hh=h; mm=m; ss=s; friend bool operator >(Time &t1,Time &t2); friend ostream & operator <<(ostream &,Time &); ; bool operator >(Time &t1,Time &t2) int re1=t1.hh*3600+t1.mm*60+t1.ss; int re2=t2.hh*3600+t2.mm*60+t2.ss; if(re1>re2) return true; else return false; ostream &operator <<(ostream &output,Time&t) output<<t.hh<<" "<<t.mm<<" "<<t.ss; return output; class date private: int year; int month; int day; public: date() year = 0; month = 0; day = 0; void set(int y,int m,int d) year=y; month=m; day=d; friend bool operator >(date &d1,date &d2); friend ostream & operator <<(ostream &,date &); ; bool operator >(date &d1,date &d2) int re1=d1.year*365+d1.month*30+d1.day; int re2=d2.year*365+d2.month*30+d2.day; if(re1>re2) return true; else return false; ostream & operator <<(ostream &output,date &d) output<<d.year<<" "<<d.month<<" "<<d.day; return output; template <class T> T maxn(T x[], int len) T max; max=x[0]; for(int i=0; i<len; i++) if(x[i]>max) max=x[i]; cout<<max<<endl; return max; int main() int intArray[100]; double douArray[100]; Time TimeArray[100]; date dateArray[100]; int ch; int i=0; while(cin>>ch) if(ch==-1) break; if(ch==1) while(cin>>intArray[i]) if(intArray[i]==0) break; i++; maxn(intArray,i); if(ch==2) while(cin>>douArray[i]) if(douArray[i]==0) break; i++; maxn(douArray,i); if(ch==3) int hour,minute,second; while(cin>>hour) if(hour==0) break; cin>>minute>>second; TimeArray[i].set(hour,minute,second); i++; maxn(TimeArray,i); if(ch==4) int years,months,days; while(cin>>years) if(years==0) break; cin>>months>>days; dateArray[i].set(years,months,days); i++; maxn(dateArray,i); return 0;
PTA的Python练习题(十九)
好久没写题目了,最近C语言也快忘得差不多了,要孰能生巧
1.
def fn(m, n):
sum=res=0
for i in range(1, n+1):
sum=sum+m
m=m*10
res=res+sum
return res
2.
我以为我看懂题目了,其实没有
def isPrime(num): num=int(num) for i in range(2,num): if num%i==0 : return False if(num!=1): return True def PrimeSum(a,b): sum=0 for i in range(a,b+1): if isPrime(i): sum+=i return sum
这里要定义两个函数,第二个函数算sum时候会调用第一个函数判断是否是素数
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