python 练习题

Posted 2020-12-19 muzii

1.【编码实现】有如下数组，需要将每个字符串中排列在任意 x 前?的所有 y 替换为 0 ，需要计算出

每个字符串需要被替换的 y 的个数，请使???您熟悉的编程语?实现。

[‘xxyyxyyyyyxxx‘, ‘yxxxx‘, ‘xyyyxxyx‘, ‘xxxx‘, ‘xxxyyy‘]

import re
list1 = [‘xxyyxyyyyyxxx‘, ‘yxxxx‘, ‘xyyyxxyx‘, ‘xxxx‘, ‘xxxyyy‘,‘yxxxyyy‘]
list2 = []
sum=0
for str1 in list1:
    
    while True:
        searchObj = re.search(‘(y+)x‘,str1)
        if searchObj:
            index=searchObj.span()
            sum = sum + index[1]-index[0]-1
            str1=str1.replace(str1[index[0]:index[1]-1],(index[1]-1-index[0])*‘0‘,1)
        else:
            list2.append(str1)
            break
print(‘sum(y):‘,sum)
print(‘replace list:‘,list2)

打印结果：

 

 2.【编码实现】请使???您熟悉的编程语?实现如下数据结构转换

list = [
 { id: 1, type: ‘human‘, name: ‘?晗‘ },
 { id: 2, type: ‘robot‘, name: ‘伊娃‘ },
 { id: 3, type: ‘animal‘, name: ‘??‘ },
 { id: 4, type: ‘human‘, name: ‘蔡徐坤‘ },
 { id: 5, type: ‘robot‘, name: ‘夏娃‘ }
];
转换为：
{
 ‘human‘: [{ id: 1, name: ‘?晗‘ },{ id: 4, name: ‘蔡徐坤‘ }],
 ‘robot‘: [{ id: 2, name: ‘伊娃‘ },{ id: 5, name: ‘夏娃‘ }],
 ‘animal‘: [{ id: 3, name: ‘??‘ }],
}

实现代码：

list = [
    { ‘id‘: 1, ‘type‘: ‘human‘, ‘name‘: ‘?晗‘ },
    { ‘id‘: 2, ‘type‘: ‘robot‘, ‘name‘: ‘伊娃‘ },
    { ‘id‘: 3, ‘type‘: ‘animal‘, ‘name‘: ‘??‘ },
    { ‘id‘: 4, ‘type‘: ‘human‘, ‘name‘: ‘蔡徐坤‘ },
    { ‘id‘: 5, ‘type‘: ‘robot‘, ‘name‘: ‘夏娃‘ }
]

dict1 = {}
方法1：
for i in range(0,len(list)):
    s = list[i].pop(‘type‘)
    if s in dict1.keys():
        dict1[s].append(list[i])
    else:
        list2 = []
        list2.append(list[i])
        dict1[s]=list2    
print(dict1)
方法2：
for item in list:
    if item[‘type‘] in dict1.keys():
        s=item.pop(‘type‘)
        dict1[s].append(item)
        #print(‘dict1‘,dict1)
    else:   
        list2=[]
        s=item.pop(‘type‘)     
        list2.append(item)
        # print(‘list2‘,list2)
        dict1[s] = list2
        # print(‘dict1‘,dict1)
prin(dict1)

打印结果：