Python 根据地址获取经纬度

Posted 2020-08-28

方法一：

使用Geopy包 ： https://github.com/geopy/geopy   （仅能精确到城镇，具体街道无结果返回）

from geopy.geocoders import Nominatim

#使用geopy查询
def geocodeN(address):
    gps=Nominatim()
    location=gps.geocode(address)
    return location.longitude,location.latitude

 

方法二：

使用高德地图或百度地图API，key可去官网申请替换

import requests

#使用高德API
def geocodeG(address):
    par = {‘address‘: address, ‘key‘: ‘cb649a25c1f81c1451adbeca73623251‘}
    base = ‘http://restapi.amap.com/v3/geocode/geo‘
    response = requests.get(base, par)
    answer = response.json()
    GPS=answer[‘geocodes‘][0][‘location‘].split(",")
    return GPS[0],GPS[1]

#使用百度API
def geocodeB(address):
    base = url = "http://api.map.baidu.com/geocoder?address=" + address + "&output=json&key=f247cdb592eb43ebac6ccd27f796e2d2"
    response = requests.get(base)
    answer = response.json()
    return answer[‘result‘][‘location‘][‘lng‘],answer[‘result‘][‘location‘][‘lat‘]

 

计算两个经纬度间距离：

from math import radians, cos, sin, asin, sqrt

#计算两点间距离-m
def geodistance(lng1,lat1,lng2,lat2):
    lng1, lat1, lng2, lat2 = map(radians, [lng1, lat1, lng2, lat2])
    dlon=lng2-lng1
    dlat=lat2-lat1
    a=sin(dlat/2)**2 + cos(lat1) * cos(lat2) * sin(dlon/2)**2 
    dis=2*asin(sqrt(a))*6371*1000
    return dis