python：成绩雷达图和手绘图片

Posted 2020-12-08 Jessie-

python123成绩雷达图

import numpy as np
import matplotlib.pyplot as plt
import matplotlib
matplotlib.rcParams[\'font.family\']=\'SimHei\'
matplotlib.rcParams[\'font.sans-serif\']=[\'SimHei\']
labels=np.array([\'第二周\',\'第三周\',\'第四周\',\'第五周\',\'第六周\'])
nAttr=5
Python=np.array([91,90,100,95,75])
angles=np.linspace(0,2*np.pi,nAttr,endpoint=False)
Python=np.concatenate((Python,[Python[0]]))
angles=np.concatenate((angles,[angles[0]]))
fig=plt.figure(facecolor="white")
plt.subplot(111,polar=True)
plt.plot(angles,Python,\'bo-\',color=\'g\',linewidth=2)
plt.fill(angles,Python,facecolor=\'g\',alpha=0.2)
plt.thetagrids(angles*180/np.pi,labels)
plt.figtext(0.52,0.95,\'2019310143107的python成绩分析图\',ha=\'center\')
plt.grid(True)
plt.savefig(\'dota_radar.JPG\')
plt.show()

 

 手绘图片

原图：

 

 

from PIL import Image
import numpy as np
a = np.asarray(Image.open("D:\\浏览器\\picture.png").convert(\'L\')).astype(\'float\')

depth = 10.  # (0-100)
grad = np.gradient(a)  # 取图像灰度的梯度值
grad_x, grad_y = grad  # 分别取横纵图像梯度值
grad_x = grad_x * depth / 100.
grad_y = grad_y * depth / 100.
A = np.sqrt(grad_x ** 2 + grad_y ** 2 + 1.)
uni_x = grad_x / A
uni_y = grad_y / A
uni_z = 1. / A

vec_el = np.pi / 2.2  # 光源的俯视角度,弧度值
vec_az = np.pi / 4.  # 光源的方位角度,弧度值
dx = np.cos(vec_el) * np.cos(vec_az)  # 光源对 x轴的影响
dy = np.cos(vec_el) * np.sin(vec_az)  # 光源对 y轴的影响
dz = np.sin(vec_el)  # 光源对z 轴的影响

b = 255 * (dx * uni_x + dy * uni_y + dz * uni_z)  # 光源归一化
b = b.clip(0, 255)

im = Image.fromarray(b.astype(\'uint8\'))  # 重构图像
im.save("D:\\浏览器\\picture.png")