mysql 查询结果求和

Posted 2023-05-01

SELECT i.uid,deposit+ddeposit+money as allmoney FROM pw_memberinfo i LEFT JOIN pw_members m ON m.uid=i.uid LEFT JOIN pw_memberdata d ON i.uid=d.uid sum(allmoney) where deposit+ddeposit+money>2000;

怎么求 allmoney字段结果的合

sum() 应该加在什么地方？

1、创建三张测试表，

create table pw_memberinfo(uid int, name varchar(20));

create table pw_members(companyid int, uid int);

create table pw_memberdata(uid int, deposit int, ddeposit int, money int);

2、三张表，分别插入测试数据，

insert into pw_members values(1, 1);

insert into pw_members values(1, 2);

insert into pw_members values(1, 3);

insert into pw_memberinfo values(1, 'name_1');

insert into pw_memberinfo values(2, 'name_2');

insert into pw_memberinfo values(3, 'name_3');

insert into pw_memberdata values(1,30,50,150);

insert into pw_memberdata values(2,77,50,12);

insert into pw_memberdata values(3,44,50,82);

3、查看pw_memberdata表中的记录，select * from pw_memberdata t，

4、编写sql语句，

select * from (SELECT i.uid, sum(deposit+ddeposit+money) as allmoney 

FROM pw_memberinfo i 

LEFT JOIN pw_members m ON m.uid=i.uid 

LEFT JOIN pw_memberdata d ON i.uid=d.uid 

group by i.uid

) t where allmoney>200

参考技术A SELECT i.uid,deposit+ddeposit+money as allmoney FROM

------------->

SELECT i.uid,sum(deposit+ddeposit+money) as allmoney FROM

另外,因为你是多个表的左联接,考虑到有NULL记录的存在,建议你用函数ifnull处理下,避免由于NULL而造成结果有误,最终改成这样:

SELECT i.uid,sum(ifnull(deposit,0)+ifnull(ddeposit,0)+ifnull(money,0)) as allmoney
FROM pw_memberinfo i LEFT JOIN pw_members m ON m.uid=i.uid LEFT JOIN pw_memberdata d ON i.uid=d.uid
where ifnull(deposit,0)+ifnull(ddeposit,0)+ifnull(money,0)>2000;本回答被提问者采纳 参考技术B SELECT i.uid,sum(deposit+ddeposit+money) as allmoney 参考技术C 我是来顶 vinson_shen 的答案的 参考技术D 来顶顶，不懂。。嘻嘻

oracle对查询到的数据进行求和统计

对查询结果中的列中的数据进行统计求和，求和结果作为新的一行添加到查询结果的末尾，

SELECT 
  CASE WHEN text IS NOT NULL THEN text ELSE\'合计\'END text,
  CASE WHEN text IS NOT NULL THEN id ELSE 0 END id,
  SUM(total_num)AS total_num
FROM (SELECT text,
       (CASE 
         WHEN ID = 1 THEN 1
         WHEN ID = 2 THEN 2
         WHEN ID = 3 THEN 4
         WHEN ID = 4 THEN 4
         WHEN ID = 5 THEN 5
         WHEN ID = 6 THEN 4
         WHEN ID = 7 THEN 4
        END) id,
        SUM(total_num) total_num
      FROM (
           SELECT aa.id, aa.text, 1 total_num  
           FROM (
                SELECT 1 id,\'AAA\' text FROM dual
                UNION
                SELECT 2 id,\'BBB\' text FROM dual
                UNION
                SELECT 3 id,\'CCC\' text FROM dual
                UNION
                SELECT 4 id,\'CCC\' text FROM dual
                UNION
                SELECT 6 id,\'CCC\' text FROM dual
                UNION
                SELECT 7 id,\'CCC\' text FROM dual
                UNION
                SELECT 5 id,\'DDD\' text FROM dual
                )aa 
           )
            GROUP BY text,(CASE 
                            WHEN id = 1 THEN 1
                            WHEN id = 2 THEN 2
                            WHEN id = 3 THEN 4
                            WHEN id = 4 THEN 4
                            WHEN id = 5 THEN 5
                            WHEN id = 6 THEN 4
                            WHEN id = 7 THEN 4
                           END )     
            ORDER BY id
) A
GROUP BY rollup(text,id)  
HAVING text IS NULL OR id IS NOT NULL

 

查询结果中就这样多了一个统计行：