python实现发工资脚本

Posted 2020-08-27

好开心啊，在旁边大神的帮助下，终于实现了发工资的python脚本，之前用shell写的老出错，刚才测试，发80个人工资详情，妥妥的，代码如下：

from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
from email.header import Header
#from handle_data_for_salary import main
#import handle_data_for_salary
import smtplib
import xlrd
import xdrlib,sys
def open_excel(file=‘test1.xls‘):
    try:
        data = xlrd.open_workbook(file)
        return data
    except Exception as e:
        print(str(e))
def excel_table_byname(file=‘test1.xls‘,colnameindex=0,by_name=‘Sheet1‘):
    data = open_excel(file)
    table = data.sheet_by_name(by_name)
    nrows = table.nrows #行数
    colnames = table.row_values(colnameindex) #某一行数据
    list = []
    for rownum in range(2,nrows):
        row = table.row_values(rownum)
        if row:
            app = {}
            for i in range(len(colnames)):
                app[colnames[i]] = row[i]
            list.append(app)
    return list

def get_value():
    tables = excel_table_byname()
    for row in tables:
            global mail
            mail = row["邮箱地址"]
            global name
            name = row["姓名"]
            global context
            authInfo = {}
            authInfo[‘server‘] = ‘smtp.163.com‘
            authInfo[‘user‘] = ‘[email protected]‘
            authInfo[‘password‘] = ‘邮箱密码‘
            fromAdd = ‘[email protected]‘
            subject = ‘Email Subject‘
            context = str(row)
            toAdd = [mail, ]
            sendEmail(authInfo, fromAdd, toAdd, subject, context)

def sendEmail(authInfo, fromAdd, toAdd, subject, plainText):

        strFrom = fromAdd
        strTo = ‘; ‘.join(toAdd)

        server = authInfo.get(‘server‘)
        smtpPort = 25
        sslPort = 465
        user = authInfo.get(‘user‘)
        passwd = authInfo.get(‘password‘)

        if not (server and user and passwd) :
                print(‘incomplete login info, exit now‘)
                return

        # 设定root信息
        msgRoot = MIMEMultipart(‘related‘)
        msgRoot[‘Subject‘] = subject
        msgRoot[‘From‘] = ‘%s<%s>‘ % (Header(‘工资详情‘, ‘utf-8‘), strFrom)
        msgRoot[‘To‘] = strTo

        # 邮件正文内容
        msgText = MIMEText(plainText, ‘plain‘, ‘utf-8‘)
        msgRoot.attach(msgText)

        msgAlternative = MIMEMultipart(‘alternative‘)
        msgRoot.attach(msgAlternative)
        try:
                #发送邮件
                smtp = smtplib.SMTP()
                smtp.connect(server, smtpPort)
                #ssl加密方式，通信过程加密，邮件数据安全
                # smtp = smtplib.SMTP_SSL()
                # smtp.connect(server, sslPort)

                #设定调试级别，依情况而定
                # smtp.set_debuglevel(1)
                smtp.login(user, passwd)
                smtp.sendmail(strFrom, toAdd, msgRoot.as_string())
                smtp.quit()
                print("邮件发送给%s成功!"%(name))
        except Exception as e:
                print("失败：" + str(e))

if __name__ == ‘__main__‘ :
        get_value()
        

注意：python环境为3.5，实验环境在windows，使用工具为pycharm，需要用到的模块:pip3 install xlrd，其中的工资表，如下图截图部分所示：后面还有很多列，看自己的需求加不，反正都是一列一列的数据

 

实验结果如下：

现在只是实现了需求，发的邮件多了估计有问题，还有邮件的格式太丑了，等下回家再改改，加油加油