python函数

Posted 2020-11-30 海纳柏川

collatz序列

def  collatz(number):
    if number%2==0:
        return number//2
    if number%2==1:
        return 3*number+1
try:        
    c=input("请输入一个数：")
    c=int(c)
except:
    print("error!")    
print(collatz(c))