python：递归算法求和1-100

Posted 2020-11-21 狮山的达

#递归算法求和1-100
def qiehe():
    def he(lis):
        if lis == []:
            return 0
        return lis[0] + he(lis[1:len(lis)])
    s = []
    n = input("请输入数字：")
    for i in range(1, int(n)):
        s.append(i)
    print(he(s))
qiehe()

def sum(max):
    if max <= 100 and max >= 0:
        return max +sum(int(max) - 1)
    else:
        return 0
print(sum(100))