python oracle 查询返回字典

Posted 2020-11-06 Go_Forward

from: https://sourceforge.net/p/cx-oracle/mailman/message/27145597/

I‘d do it with a "row factory", here are two examples, one which builds a dictionary, the other one builds a "named tuple" and is very similar to sqlite3.Row.

def makeDictFactory(cursor):
    columnNames = [d[0] for d in cursor.description]
    def createRow(*args):
        return dict(zip(columnNames, args))
    return createRow

def makeNamedTupleFactory(cursor):
    columnNames = [d[0].lower() for d in cursor.description]
    import collections
    Row = collections.namedtuple(‘Row‘, columnNames)
    return Row

Then, just after the cs.execute() call, you can add:

cs.rowfactory = makeDictFactory(cs)
# or
cs.rowfactory = makeNamedTupleFactory(cs)

-- 
#Amaury Forgeot d‘Arc