python 报错TypeError: 'range' object does not support item assignment，解决方法

Posted 2020-10-25 苏杺

贴问题

nums = range(5)#range is a built-in function that creates a list of integers
print(nums)#prints "[0,1,2,3,4]"
print(nums[2:4])#Get a slice from index 2 to 4 (exclusive); prints \'[2,3]"
print(nums[2:])#Get a slice from index 2 to the end; prints "[2,3,4]"
print(nums[:2])#Get a slice from the start to index 2 (exclusive); prints "[0,1]"
print(nums[:])#Get a slice of the whole list ; prints "[0,1,2,3,4]"
print(nums[:-1])#Slice indices can be negative; prints "[0,1,2,3]"
nums[2:4] = [8,9]      # Assign a new sublist to a slice
print(nums)#prints "[0,1,8,9,4]"

2.报错的原因：

尝试使用range() 
创建整数列表（导致“TypeError: ‘range’ object does not support item assignment”）有时你想要得到一个有序的整数列表，所以range() 看上去是生成此列表的不错方式。然而，你需要记住range() 返回的是“range object”，而不是实际的list 值。

3.解决方法：

将上面例子的代码： nums = range(5)改为nums = list(range(5))