复数类的运算

Posted 2023-04-11 qian-heng

根据以下代码段完善 ?? 处内容及程序内容，以实现规定的输出。

class Complex

public:
Complex(double r=0, double i=0):real(r), imag(i)
Complex operator+( ?? ) const;//重载双目运算符\'+\'
Complex operator-=( ?? ); //重载双目运算符\'-=\'
friend Complex operator-( ?? ) const;//重载双目运算符\'-\'
void Display() const;
private:
double real;
double imag;
;

void Complex::Display() const

cout << "(" << real << ", " << imag << ")" << endl;

int main()

double r, m;
cin >> r >> m;
Complex c1(r, m);
cin >> r >> m;
Complex c2(r, m);
Complex c3 = c1+c2;
c3.Display();
c3 = c1-c2;
c3.Display();
c3 -= c1;
c3.Display();
return 0;

输入格式:

输入有两行，分别为两个复数的实部与虚部。

输出格式:

按样例格式输出结果。

输入样例:

在这里给出一组输入。例如：

4 2
3 -5

 

输出样例:

在这里给出相应的输出。例如：

(7, -3)
(1, 7)
(-3, 5)
代码：

#include<iostream>
using namespace std;
class Complex

public:
Complex(double r=0, double i=0):real(r), imag(i)
Complex operator+( Complex &c2) const;//重载双目运算符\'+\'
Complex operator-=( Complex &c2); //重载双目运算符\'-=\'
friend Complex operator-( Complex c1, Complex c2);//重载双目运算符\'-\'
void Display() const;
private:
double real;
double imag;
;

void Complex::Display() const

cout << "(" << real << ", " << imag << ")" << endl;

Complex Complex::operator+( Complex &c2) const

return Complex(real+c2.real,imag+c2.imag);

Complex Complex::operator-=( Complex &c2)
real-=c2.real;
imag-=c2.imag;

return Complex(real,imag);

Complex operator-( Complex c1, Complex c2)
c1.real=c1.real-c2.real;
c1.imag=c1.imag-c2.imag;
//return c1;
return c1;

int main()

double r, m;
cin >> r >> m;
Complex c1(r, m);
cin >> r >> m;
Complex c2(r, m);
Complex c3 = c1+c2;
c3.Display();
c3 = c1-c2;
c3.Display();
c3 -= c1;
c3.Display();
return 0;

java构造一个复数类

要调用窗体“请输入一个复数：”（形式是a+bi）比如输入1+2i 然后程序执行会打印出“此复数实部为：1 虚部为：2

用这个包import javax.swing.JOptionPane;
如果输入的不是a+bi形式，不用判定出错。

最讨厌不看题目一股脑COPY过来的人。

import java.awt.Dimension;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;

import javax.swing.*;
import javax.swing.WindowConstants;

public class MainFrame extends JFrame implements ActionListener

private JTextField textField;
public MainFrame()

super();
setSize(new Dimension(320, 210));
setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);
setTitle("复数");
getContentPane().setLayout(null);

textField = new JTextField();
textField.setBounds(161, 67, 123, 24);
getContentPane().add(textField);

final JLabel label = new JLabel();
label.setText("请输入一个复数");
label.setBounds(39, 70, 121, 18);
getContentPane().add(label);

final JButton button = new JButton();
button.setText("确定");
button.setBounds(161, 116, 123, 27);
button.addActionListener(this);
getContentPane().add(button);


public void actionPerformed(ActionEvent e)

String complexString = textField.getText();
if(!complexString.matches("\\d+\\+\\d+i"))

return;

String[] numGroup = complexString.split("\\+");
String a = numGroup[0];
String b = numGroup[1].substring(0, numGroup[1].length() - 1);
JOptionPane.showMessageDialog(this
, "此复数实部为：" + a + " 虚部为：" + b
, "结果"
, JOptionPane.INFORMATION_MESSAGE);


public static void main(String[] args)

new MainFrame().show();

参考资料：csdn

参考技术A /**
* 操作复数的类Complex

* @author 周长发
* @version 1.0
*/
public class Complex

private double real = 0.0; // 复数的实部
private double imaginary = 0.0; // 复数的虚部
private double eps = 0.0; // 缺省精度

/**
* 基本构造函数
*/
public Complex()



/**
* 指定值构造函数
*
* @param dblX - 指定的实部
* @param dblY - 指定的虚部
*/
public Complex(double dblX, double dblY)

real = dblX;
imaginary = dblY;


/**
* 拷贝构造函数
*
* @param other - 源复数
*/
public Complex(Complex other)

real = other.real;
imaginary = other.imaginary;


/**
* 根据"a,b"形式的字符串来构造复数，以a为复数的实部，b为复数的虚部
*
* @param s - "a,b"形式的字符串，a为复数的实部，b为复数的虚部
* @param sDelim - a, b之间的分隔符
*/
public Complex(String s, String sDelim)

setValue(s, sDelim);


/**
* 设置复数运算的精度
*
* @param newEps - 新的精度值
*/
public void setEps(double newEps)

eps = newEps;


/**
* 取复数的精度值
*
* @return double型，复数的精度值
*/
public double getEps()

return eps;


/**
* 指定复数的实部
*
* @param dblX - 复数的实部
*/
public void setReal(double dblX)

real = dblX;


/**
* 指定复数的虚部
*
* @param dblY - 复数的虚部
*/
public void setImag(double dblY)

imaginary = dblY;


/**
* 取复数的实部
*
* @return double 型，复数的实部
*/
public double getReal()

return real;


/**
* 取复数的虚部
*
* @return double 型，复数的虚部
*/
public double getImag()

return imaginary;


/**
* 指定复数的实部和虚部值
*
* @param real - 指定的实部
* @param imag - 指定的虚部
*/
public void setValue(double real, double imag)

setReal(real);
setImag(imag);


/**
* 将"a,b"形式的字符串转化为复数，以a为复数的实部，b为复数的虚部
*
* @param s - "a,b"形式的字符串，a为复数的实部，b为复数的虚部
* @param sDelim - a, b之间的分隔符
*/
public void setValue(String s, String sDelim)

int nPos = s.indexOf(sDelim);
if (nPos == -1)

s = s.trim();
real = Double.parseDouble(s);
imaginary = 0;

else

int nLen = s.length();
String sLeft = s.substring(0, nPos);
String sRight = s.substring(nPos+1, nLen);
sLeft = sLeft.trim();
sRight = sRight.trim();
real = Double.parseDouble(sLeft);
imaginary = Double.parseDouble(sRight);



/**
* 将复数转化为"a+bj"形式的字符串
*
* @return String 型，"a+bj"形式的字符串
*/
public String toString()

String s;
if (real != 0.0)

if (imaginary > 0)
s = new Float(real).toString() + "+" + new Float(imaginary).toString() + "j";
else if (imaginary < 0)
s = new Float(real).toString() + "-" + new Float(-1*imaginary).toString() + "j";
else
s = new Float(real).toString();

else

if (imaginary > 0)
s = new Float(imaginary).toString() + "j";
else if (imaginary < 0)
s = new Float(-1*imaginary).toString() + "j";
else
s = new Float(real).toString();


return s;


/**
* 比较两个复数是否相等
*
* @param cpxX - 用于比较的复数
* @return boolean型，相等则为true，否则为false
*/
public boolean equal(Complex cpxX)

return Math.abs(real - cpxX.real) <= eps &&
Math.abs(imaginary - cpxX.imaginary) <= eps;


/**
* 给复数赋值
*
* @param cpxX - 用于给复数赋值的源复数
* @return Complex型，与cpxX相等的复数
*/
public Complex setValue(Complex cpxX)

real = cpxX.real;
imaginary = cpxX.imaginary;

return this;


/**
* 实现复数的加法
*
* @param cpxX - 与指定复数相加的复数
* @return Complex型，指定复数与cpxX相加之和
*/
public Complex add(Complex cpxX)

double x = real + cpxX.real;
double y = imaginary + cpxX.imaginary;

return new Complex(x, y);


/**
* 实现复数的减法
*
* @param cpxX - 与指定复数相减的复数
* @return Complex型，指定复数减去cpxX之差
*/
public Complex subtract(Complex cpxX)

double x = real - cpxX.real;
double y = imaginary - cpxX.imaginary;

return new Complex(x, y);


/**
* 实现复数的乘法
*
* @param cpxX - 与指定复数相乘的复数
* @return Complex型，指定复数与cpxX相乘之积
*/
public Complex multiply(Complex cpxX)

double x = real * cpxX.real - imaginary * cpxX.imaginary;
double y = real * cpxX.imaginary + imaginary * cpxX.real;

return new Complex(x, y);


/**
* 实现复数的除法
*
* @param cpxX - 与指定复数相除的复数
* @return Complex型，指定复数除与cpxX之商
*/
public Complex divide(Complex cpxX)

double e, f, x, y;

if (Math.abs(cpxX.real) >= Math.abs(cpxX.imaginary))

e = cpxX.imaginary / cpxX.real;
f = cpxX.real + e * cpxX.imaginary;

x = (real + imaginary * e) / f;
y = (imaginary - real * e) / f;

else

e = cpxX.real / cpxX.imaginary;
f = cpxX.imaginary + e * cpxX.real;

x = (real * e + imaginary) / f;
y = (imaginary * e - real) / f;


return new Complex(x, y);


/**
* 计算复数的模
*
* @return double型，指定复数的模
*/
public double abs()

// 求取实部和虚部的绝对值
double x = Math.abs(real);
double y = Math.abs(imaginary);

if (real == 0)
return y;
if (imaginary == 0)
return x;

// 计算模
if (x > y)
return (x * Math.sqrt(1 + (y / x) * (y / x)));

return (y * Math.sqrt(1 + (x / y) * (x / y)));


/**
* 计算复数的根
*
* @param n - 待求根的根次
* @param cpxR - Complex型数组，长度为n，返回复数的所有根
*/
public void root(int n, Complex[] cpxR)

if (n<1)
return;

double q = Math.atan2(imaginary, real);
double r = Math.sqrt(real*real + imaginary*imaginary);
if (r != 0)

r = (1.0/n)*Math.log(r);
r = Math.exp(r);


for (int k=0; k<=n-1; k++)

double t = (2.0*k*3.1415926+q)/n;
cpxR[k] = new Complex(r*Math.cos(t), r*Math.sin(t));



/**
* 计算复数的实幂指数
*
* @param dblW - 待求实幂指数的幂次
* @return Complex型，复数的实幂指数值
*/
public Complex pow(double dblW)

// 常量
final double PI = 3.14159265358979;

// 局部变量
double r, t;

// 特殊值处理
if ((real == 0) && (imaginary == 0))
return new Complex(0, 0);

// 幂运算公式中的三角函数运算
if (real == 0)

if (imaginary > 0)
t = 1.5707963268;
else
t = -1.5707963268;

else

if (real > 0)
t = Math.atan2(imaginary, real);
else

if (imaginary >= 0)
t = Math.atan2(imaginary, real) + PI;
else
t = Math.atan2(imaginary, real) - PI;



// 模的幂
r = Math.exp(dblW * Math.log(Math.sqrt(real * real + imaginary * imaginary)));

// 复数的实幂指数
return new Complex(r * Math.cos(dblW * t), r * Math.sin(dblW * t));


/**
* 计算复数的复幂指数
*
* @param cpxW - 待求复幂指数的幂次
* @param n - 控制参数，默认值为0。当n=0时，求得的结果为复幂指数的主值
* @return Complex型，复数的复幂指数值
*/
public Complex pow(Complex cpxW, int n)

// 常量
final double PI = 3.14159265358979;
// 局部变量
double r, s, u, v;

// 特殊值处理
if (real == 0)

if (imaginary == 0)
return new Complex(0, 0);

s = 1.5707963268 * (Math.abs(imaginary) / imaginary + 4 * n);

else

s = 2 * PI * n + Math.atan2(imaginary, real);

if (real < 0)

if (imaginary > 0)
s = s + PI;
else
s = s - PI;



// 求幂运算公式
r = 0.5 * Math.log(real * real + imaginary * imaginary);
v = cpxW.real * r + cpxW.imaginary * s;
u = Math.exp(cpxW.real * r - cpxW.imaginary * s);

return new Complex(u * Math.cos(v), u * Math.sin(v));


/**
* 计算复数的自然对数
*
* @return Complex型，复数的自然对数值
*/
public Complex log()

double p = Math.log(Math.sqrt(real*real + imaginary*imaginary));
return new Complex(p, Math.atan2(imaginary, real));


/**
* 计算复数的正弦
*
* @return Complex型，复数的正弦值
*/
public Complex sin()

int i;
double x, y, y1, br, b1, b2;
double[] c = new double[6];

// 切比雪夫公式的常数系数
c[0] = 1.13031820798497;
c[1] = 0.04433684984866;
c[2] = 0.00054292631191;
c[3] = 0.00000319843646;
c[4] = 0.00000001103607;
c[5] = 0.00000000002498;

y1 = Math.exp(imaginary);
x = 0.5 * (y1 + 1 / y1);
br = 0;
if (Math.abs(imaginary) >= 1)
y = 0.5 * (y1 - 1 / y1);
else

b1 = 0;
b2 = 0;
y1 = 2 * (2 * imaginary * imaginary - 1);
for (i = 5; i >=0; --i)

br = y1 * b1 - b2 - c[i];
if (i != 0)

b2 = b1;
b1 = br;



y = imaginary * (br - b1);


// 组合计算结果
x = x * Math.sin(real);
y = y * Math.cos(real);

return new Complex(x, y);


/**
* 计算复数的余弦
*
* @return Complex型，复数的余弦值
*/
public Complex cos()

int i;
double x, y, y1, br, b1, b2;
double[] c = new double[6];

// 切比雪夫公式的常数系数
c[0] = 1.13031820798497;
c[1] = 0.04433684984866;
c[2] = 0.00054292631191;
c[3] = 0.00000319843646;
c[4] = 0.00000001103607;
c[5] = 0.00000000002498;

y1 = Math.exp(imaginary);
x = 0.5 * (y1 + 1 / y1);
br = 0;
if (Math.abs(imaginary) >= 1)
y = 0.5 * (y1 - 1 / y1);
else

b1 = 0;
b2 = 0;
y1 = 2 * (2 * imaginary * imaginary - 1);
for (i=5 ; i>=0; --i)

br = y1 * b1 - b2 - c[i];
if (i != 0)

b2 = b1;
b1 = br;



y = imaginary * (br - b1);


// 组合计算结果
x = x * Math.cos(real);
y = -y * Math.sin(real);

return new Complex(x, y);


/**
* 计算复数的正切
*
* @return Complex型，复数的正切值
*/
public Complex tan()

return sin().divide(cos());

参考技术B 说实话^不懂