Python3 安装 numpy 科学库

Posted 2020-10-20

[[email protected] numpy]# wget https://pypi.python.org/packages/ee/66/7c2690141c520db08b6a6f852fa768f421b0b50683b7bbcd88ef51f33170/numpy-1.14.0.zip
[[email protected] numpy]# md5sum numpy-1.14.0.zip 
c12d4bf380ac925fcdc8a59ada6c3298  numpy-1.14.0.zip
[[email protected] numpy]# unzip numpy-1.14.0.zip 
[[email protected] numpy]# cd numpy-1.14.0
[[email protected] numpy-1.14.0]# cat INSTALL.rst.txt                                          #安装说明
[[email protected] numpy-1.14.0]# python3  setup.py build install --prefix /root/python/numpy  #注意安装路径
[[email protected] numpy-1.14.0]# echo "export PYTHONPATH=/root/python/numpy/lib/python3.6/site-packages" >> ~/.bashrc  #注意安装路径
[[email protected] numpy-1.14.0]# . ~/.bashrc
[[email protected] numpy-1.14.0]# echo $?
0
[[email protected] numpy-1.14.0]# 

写一个线性回归 试一试

[[email protected] work.dir]# cat SimpleLineRegression.py 
#!/usr/bin/python3

import numpy as np

def fitSLR(x,y):
    n = len(x)
    dinominator = 0
    numerator = 0
    for i in range(0, n):
        numerator += (x[i] - np.mean(x)) * (y[i] - np.mean(y))
        dinominator +=(x[i] - np.mean(x)) ** 2

    print ("numerator:", numerator)
    print ("dinominator", dinominator)
    b1 = numerator/float(dinominator)
    b0 = np.mean(y)/float(np.mean(x))

    return b0, b1

def predict(x, b0, b1):
    return b0 + x*b1

x = [1,3,2,1,3]
y = [14,24,18,17,27]

b0, b1 = fitSLR(x,y)
print ("intercept:", b0, " slope:", b1)

x_test = 6
y_test = predict(6, b0, b1)
print("y_test", y_test)

[[email protected] work.dir]# ./SimpleLineRegression.py 
numerator: 20.0
dinominator 4.0
intercept: 10.0  slope: 5.0
y_test 40.0
[[email protected] work.dir]#