python函数不定长参数

Posted 2020-10-19 许小伍

 

def fun(a, b, *args):
    print(a)
    print(b)
    print(args)
    print("="*30)
    ret = a + b
    for i in args:
        ret += i
    return ret

print(fun(1,2,3,4))

结果：
1
2
(3, 4)
==============================
10

1,2分别赋值给a,b，剩下的参数以元组的形式赋值给args

 

字典形式参数：

def fun(a, b, *args, **kwargs):
    print(a)
    print(b)
    print(args)
    print(kwargs)

fun(1, 2, 3, 4, name = "hello", age = 20)

结果：
1
2
(3, 4)
{‘name‘: ‘hello‘, ‘age‘: 20}

 

传入元组和字典：

def fun(a, b, *args, **kwargs):
    print(a)
    print(b)
    print(args)
    print(kwargs)

tup = (11,22,33)
dic = {"name":"hello", "age":20}
fun(1, 2, *tup, **dic)

结果：
1
2
(11, 22, 33)
{‘name‘: ‘hello‘, ‘age‘: 20}