Python随笔python基础

Posted 2020-10-15

一、练习：

#!usr/bin/env python 
#-*- coding:utf-8 _*-  
""" 
@author:Administrator 
@file: dictionary.py
@time: 2017/11/19 
"""
‘‘‘
有如下集合[11,22,33,44,55,66,77,88,99,110,121,132,143,154,165,176,187]，将所有大于66的值保存在字典的第一个key中，将小于66的值保存在第二个key的值中
即：{‘k1‘：大于66，‘k2‘:小于66}
‘‘‘
######方法一
#dic = {}
#all_list = [11,22,33,44,55,66,77,88,99,110,121,132,143,154,165,176,187]
#for i in all_list:
#    if i > 66:
#        if "k1" in dic.keys():
#            dic["k1"].append(i)
#        else:
#            dic[‘k1‘] = [i,]
#    else:
#        if "k2" in dic.keys():
#            dic["k2"].append(i)
#        else:
#            dic[‘k2‘] = [i,]
#print(dic[‘k1‘])
#print(dic[‘k2‘])

#方法二、
all_list = [11,22,33,44,55,66,77,88,99,110,121,132,143,154,165,176,187]
dic = {‘k1‘:[],‘k2‘:[]}
for item in all_list:
    if item>66:
        dic["k1"].append(item)
    else:
        dic["k2"].append(item)
print(dic[‘k1‘])
print(dic[‘k2‘])

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