Zabbix调用外部脚本发送邮件：python编写脚本

Posted 2020-10-13 愤怒的绿萝

Zabbix调用外部脚本发送邮件的时候，会在命令行传入两个参数，第一个参数就是要发送给哪个邮箱地址，第二个参数就是邮件信息，为了保证可以传入多个参数，所以假设有多个参数传入

#!/usr/bin/env python
#encoding:utf8
#
# Zabbix Server 发送邮件脚本
# 

from email import encoders
from email.header import Header
from email.mime.text import MIMEText
from email.utils import parseaddr, formataddr
import smtplib
import sys

from_addr = \'[e-mail]\'
password = \'xxxxxx\'
smtp_server = \'smtp.163.com\'

# 报警邮件收件人
to_addr = sys.argv[1]


def _format_addr(s):
    name, addr = parseaddr(s)
    return formataddr(( \\
        Header(name, \'utf-8\').encode(), \\
        addr.encode(\'utf-8\') if isinstance(addr, unicode) else addr))

def ZabbixInfo():
    res = ""
    itemList = sys.argv
    for index in range(2, len(itemList)):
        res = res + itemList[index]
    return res
    
def sendMsg():
    bodyInfo = ZabbixInfo()
    headerInfo = str(bodyInfo.split(\'<*>\')[1])
    fromInfo = u"Zabbix监控"

    msg = MIMEText(bodyInfo , \'plain\', \'utf-8\')
    msg[\'From\'] = _format_addr(fromInfo + "<%s>" % from_addr)
    msg[\'To\'] = _format_addr(fromInfo + "<%s>" % to_addr)
    msg[\'Subject\'] = Header(headerInfo, \'utf-8\').encode()

    return msg.as_string()

def main():
    server = smtplib.SMTP(smtp_server, 25)
    #server.set_debuglevel(1)
    server.login(from_addr, password)
    server.sendmail(from_addr, [to_addr], sendMsg())
    server.quit()

if __name__ == "__main__":
    main()

 

 

脚本中的163邮箱的密码不是登陆密码，是pop3方式的专用密码

下面是日志图片，使用的zabbix版本比较老，保证运行稳定，少BUG