朋友,您好,我想问Django分页后查询条件丢失的问题
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刚学习Django写了一个搜索的视图函数,想对搜索内容进行分页,现在有个问题,搜索内容提交后可以正常分页并显示第一页,选择第二个页时由于GET内容没传过去页面就显示不出来,请问哪个大神有好的解决办法 这是我的控件部分:查询部分
<form action="." method="GET"> <fieldset id="search_fieldset" style="paddng:20px;background:#3CF; border:#ccc 1px solid"> <input type="text" name="q" value="query | escape" class="input_text"> <input type="submit" value="Search" class="search_button"> </fieldset> </form>
分页部分
<div class = "pagination">
<span class="step-links">
% if results.has_previous %
# 这里需要将原来的条件传递过来 #
<a href="?page=results.previous_page_number&q=">previous</a>
% endif %
<span class = "current">
Pageresults.number of results.paginator.num_pages
</span>
% if results.has_next %
<a href="?page=apps.next_page_number&q=">next</a>
% endif %
</span>
</div>
网上有人说需要把查询条件放在 <a href="?page=results.previous_page_number&q=">previous</a>的&q=中,但我不知道这里面放什么,希望朋友您能教一下,十分感谢
很简单的GET传值,晚上再回答吧,现在有点事...
给你个示例代码吧
# views.pydef order_forms_by_days(request):
"""
订单日统计报表,读取 本地 count_days 表
:param request:
:return:
"""
cursor = connections['mfashion_db'].cursor()
sql = 'SELECT * FROM count_days ORDER BY date DESC'
cursor.execute(sql)
results = dictfetchall(cursor)
limit = 20
paginator = Paginator(results, limit)
page = request.GET.get('page')
try:
orders = paginator.page(page)
except(PageNotAnInteger, EmptyPage):
orders = paginator.page(1)
params =
'request': request,
'orders': orders,
'page': page
return render_to_response('boss/census_days.html', params, context_instance=RequestContext(request))% with orders as datas %
<div class="ui page grid floated" style="margin-top: 30px;">
<div class="column">
<h2>订单日统计报表</h2>
订单总数量: <h3> all_counts </h3>总金额(元): <h3> all_price </h3>
<table class="ui compact small striped table">
<thead>
<tr>
<th>订单编号</th>
<th>下单时间</th>
<th>支付时间</th>
<th>买家姓名</th>
<th>卖家名称</th>
<th>订单状态</th>
<th>商品名称</th>
<th>订单金额</th>
</tr>
</thead>
<tbody>
% for order in orders %
<tr>
<td> order.trade_no </td>
<td> order.create_time </td>
<td> order.paid </td>
<td> order.shipped </td>
<td> order.sign </td>
<td> order.completed </td>
<td> order.cancelorder </td>
<td> order.deliveryfailure </td>
<td> order.refund </td>
<td> order.refuseorders </td>
<td> order.closeorders </td>
<td> order.total </td>
</tr>
% endfor %
</tbody>
</table>
<div class="ui two column centered grid">
<div class="column centered row">
<div class="ui pagination menu">
% if datas.has_previous %
<a class="icon item"
href="?% url_replace request 'page' datas.previous_page_number %">
<i class="left arrow icon"></i>
</a>
% else %<a class="disabled icon item"><i class="left arrow icon"></i>
</a>
% endif %
<div class="item">
datas.number / datas.paginator.num_pages
</div>
% if datas.has_next %
<a class="icon item"
href="?% url_replace request 'page' datas.next_page_number %">
<i class="right arrow icon"></i>
</a>
% else %<a class="disabled icon item"><i class="right arrow icon"></i>
</a>
% endif %
</div>
</div>
</div>
</div>
</div>
% endwith %来自:求助得到的回答 参考技术A
给你个Pager类的源代码吧:
class Pager:def __init__(self,size,offset,request):
self.offset = offset;
self.path = request.path;
self.query_dict = request.GET.copy()
self.size = size;
def has_previous(self):
if self.offset>0:
return True
else:
return False
def has_next(self):
if self.size>20:
return True
else:
return False
def previous_url(self):
if self.has_previous():
self.query_dict["offset"]=self.offset-20
return self.path+"?"+self.query_dict.urlencode()
else:
return None
def next_url(self):
if self.has_next():
self.query_dict["offset"]=self.offset+20
return self.path+"?"+self.query_dict.urlencode()
else:
return None
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