JAVA 日期 INT变量小于10时，怎么给它补0，求解

Posted 2023-03-28

int year;
int month;
int day;

GregorianCalendar timenow=new GregorianCalendar();
year=timenow.get(Calendar.YEAR);
month=timenow.get(Calendar.MONTH)+1;
day=timenow.get(Calendar.DAY_OF_MONTH);

String alltime=year+"-"+month+"-"+day;

怎么让其变为“xxxx-yy-zz”的格式？？

参考技术A 给你个例子吧

import java.text.*;
import java.util.*;

public class GetTime
public static void main(String[] args)
MyThread mt = new MyThread();
mt.start();



class MyThread extends Thread

public void run()
while(true)
Date d=new Date();//获取时间
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd kk:mm:ss ");//转换格式
System.out.println(sdf.format(d));//打印

try
Thread.sleep(1000);
catch(InterruptedException e)
e.printStackTrace();




本回答被提问者采纳 参考技术B SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Calendar cc = Calendar.getIntance();
String time = sdf.parse(cc.getTime()); 参考技术C public static void main(String[] args)
Date d = new Date();
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");
String alltime = format.format(d);
System.out.println(alltime);