练习——稀疏数组的简单应用

Posted 2023-03-28 Q1u-ovo

package com.q1u.array;

public class ArrayDemo08 
    public static void main(String[] args) 
        //1.创建一个二维数组    11*11   0：没有棋子  1：黑棋    2：白棋

        int[][] array1 = new int[11][11];
        array1[1][2] = 1;
        array1[2][3] = 2;
        //输出原始数组
        System.out.println("输出原始数组：");
        for (int[] ints : array1) 
            for (int anInt : ints) 
                System.out.print(anInt+"\\t");
            
            System.out.println();
        

        System.out.println("===============================");

        //转换为稀疏数组保存
        //1.获取有效值个数
        int sum = 0;
        for (int i = 0; i < 11; i++) 
            for (int j = 0; j < 11; j++) 
                if (array1[i][j]!=0)
                    sum++;
                
            
        
        System.out.println("有效值个数:"+sum);

        //2.创建一个稀疏数组
        int[][] array2 = new int[sum+1][3];

        array2[0][0] = 11;
        array2[0][1] = 11;
        array2[0][2] = sum;

        //3.遍历二维数组，将非零的值存放到稀疏数组中
        int count = 0;
        for (int i = 0; i < array1.length; i++) 
            for (int j = 0; j < array1[i].length; j++) 
                if (array1[i][j]!=0)
                    count++;
                    array2[count][0] = i;
                    array2[count][1] = j;
                    array2[count][2] = array1[i][j];
                
            
        

        //4.输出稀疏数组
        System.out.println("输出稀疏数组:");
        for (int i = 0; i < array2.length; i++) 
            System.out.print(array2[i][0]+"\\t");
            System.out.print(array2[i][1]+"\\t");
            System.out.println(array2[i][2]);
        

        System.out.println("==================================");
        System.out.println("还原");
        //1.读取稀疏数组
        int[][] array3 = new int[array2[0][0]][array2[0][1]];

        //2.给其中元素还原他的值
        for (int i = 1; i < array2.length; i++) 
            array3[array2[i][0]][array2[i][1]] = array2[i][2];
        

        //3.打印
        System.out.println("输出还原的数组：");
        for (int[] ints : array3) 
            for (int anInt : ints) 
                System.out.print(anInt+"\\t");
            
            System.out.println();