Python3的列表推导式

Posted 2020-10-07

# -*- coding: utf-8 -*-

li = [1,2,3,4,5,6,7,8,9]
print ([x**2 for x in li])

print ([x**2 for x in li if x>5])

print (dict([(x,x*10) for x in li]))

print  ([ (x, y) for x in range(10) if x % 2 if x > 3 for y in range(10) if y > 7 if y != 8 ])

vec=[2,4,6]
vec2=[4,3,-9]
sq = [vec[i]+vec2[i] for i in range(len(vec))]
print (sq)

print ([x*y for x in [1,2,3] for y in  [1,2,3]])

testList = [1,2,3,4]
def mul2(x):
    return x*2
print ([mul2(i) for i in testList])